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x---->
<---y
www.PROJEKTOMANIA.com Temat = 13
α = 0.32
β = 0.6
γ = 1.28
2
L = 5.22
m
EJ = 1128 kNm
x = α
x = 0.32
y = 1 − α = .68
1
2
M
= M − ⋅ ⋅
A
MB
q L
B
2
1. Postac wyboczenia 1.1 Równanie rózniczkowe osi odksztalconej Przedzial II
Przedzial I
0 < x < α ⋅L
0 < y < L − α ⋅L
1
2
M
=
+
⋅ − ⋅ ⋅
1
y(x)
MA VA x
q x
2
2
M
=
− ⋅ ⋅
y(y)
MB
q y
2
2
EJ⋅
1
w''
=
⋅ ⋅
−
⋅ −
I(x)
q x
V
M
2
2
A x
A
β⋅EJ⋅
1
w''
=
⋅ ⋅
−
II(y)
q y
M
2
B
3
2
EJ⋅
1
w'
=
⋅ ⋅
1
−
⋅
−
⋅ +
I(x)
q x
V
M
C
3
6
2 A x
A x
1
β⋅EJ⋅
1
w'
=
⋅ ⋅
−
⋅ +
II(y)
q y
M
C
6
B y
2
4
3
1
2
EJ⋅
1
w
=
⋅ ⋅
1
− ⋅
⋅
− ⋅
⋅
+
⋅ +
I(x)
q x
V
x
M
x
C
D
4
2
24
6
A
2
A
1 x
1
β⋅EJ⋅
1
w
=
⋅ ⋅
1
− ⋅
⋅
+
⋅ +
II(y)
q y
M
y
C
D
24
2
B
2 y
2
1.2 Wyznaczenie stalych z warunków brzegowych 1) w (0) = 0
I
2) w' (0) = 0
I
3) w` (0) = 0
II
4) w' (αL) = -w' (L-αL) I
II
5) w (αL) =w (L-αL) I
II
2
3
3
M
= −
⋅
=
⋅
=
⋅
A
0.3613
q L
C1 0
q L
C2 0
q L
4
V
=
⋅
=
⋅
A
1
q L
D1 0
q L
4
D =
⋅
2
0.03125
q L
2
M
=
⋅
B
0.1387
q L
Wynik kontrolny w'(αL): 2
1
⋅
⋅
3
2
3
2
q⋅
1
x −
V ⋅
− M ⋅ +
1
C
=
⋅q⋅
1
x −
⋅1⋅x − (−0.3613)⋅x + 0 =
q L
0.06988
Kontrola = 0.06987
6
2 A x
A x
1
6
2
EJ
2. Obciazenie krytyczne 2.1 Kryterium energetyczne Timoshenki
⌠
⌠
⎮
2
⎮
2
EJ⋅w'' dx
⎮
+
N⋅w'
x
⎮
d = 0
⌡
⌡
I)
1 ⎛ 1
3
2
2
⎞
1 ⎡1
3
2
2
⎤
w'
=
⋅⎜ ⋅ ⋅
1
− ⋅
⋅ ⋅ ⋅ −
⋅ ⋅ ⋅
+
⎟ =
⋅⎢ ⋅ ⋅
1
− ⋅ ⋅ ⋅ ⋅ − (−
⋅ ⋅ ⋅
+ ⎥
I(x)
q x
VA x q L MA x q L
C1
q x
1 x q L
0.3613) x q L
0
EJ ⎝ 6
2
⎠
EJ ⎣6
2
⎦
1 ⎛ 1
2
2⎞
1 ⎡1
2
2⎤
w''
=
⋅⎜ ⋅ ⋅ −
⋅ ⋅ ⋅ −
⋅ ⋅ ⎟ =
⋅⎢ ⋅ ⋅ − ⋅ ⋅ ⋅ − (−
⋅ ⋅ ⎥
I(x)
q x
VA x q L MA q L
q x
1 x q L
0.3613) q L
EJ ⎝ 2
⎠
EJ ⎣2
⎦
N x = (− − γ ⋅
= [(−
−
⋅
I(x)
1
) P
1)
1.28] P
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1
⎛ 1
3
⎞
1
⎛ 1
3
⎞
w'
=
⋅⎜ ⋅ ⋅ −
⋅ +
⎟ =
⋅⎜ ⋅ ⋅ −
⋅ + ⎟
II(x)
q y
M
C
q y
0.1387 y
0
β⋅
B y
2
EJ ⎝ 6
⎠
0.6⋅EJ ⎝ 6
⎠
1
⎛ 1
2
⎞
1
⎛ 1
2
⎞
w''
=
⋅⎜ ⋅ ⋅ −
⎟ =
⋅⎜ ⋅ ⋅ −
⎟
II(x)
q y
M
q y
0.1387
β⋅
B
EJ ⎝ 2
⎠
0.6⋅EJ ⎝ 2
⎠
N
= −
II(x)
P
2.2 Wartosc krytyczna sily P
α⋅L
⌠
L−α⋅L
α⋅L
L−α⋅L
⎮
⌠
⌠
⌠
2
⎮
2
⎮
2
⎮
2
EJ⋅w''
dx
⎮
+
β⋅ ⋅
− ⋅
(
+ ⋅
− ⋅
=
I
EJ w''
y
d
P
1
γ) w'
x
d
P
w'
y
d
0
⌡
⎮
II
⌡
⎮
I
⌡
⎮
II
⌡
0
0
0
0
0.32⋅L
⌠
L−0.32⋅L
0.32⋅L
L−0.32⋅L
⎮
⌠
⌠
⌠
2
⎮
2
⎮
2
⎮
2
=
EJ⋅w''
x
⎮
+
⋅ ⋅
− ⋅
⋅
− ⋅
I d
.6 EJ w''
y
d
P
2.28 w'
dx
P
w'
y
d
⌡
⎮
II
⌡
⎮
I
⌡
⎮
II
⌡
0
0
0
0
α⋅L
⌠
0.32⋅L
⌠
⎮
⎡
2
⎮
2
1 ⎛ 1
2
⎞⎤
1 ⎛ 1
2
⎞
I
= ⎮
⋅⎢ ⎜ ⋅ ⋅ −
⋅ ⋅ ⋅ −
⋅ ⋅ ⎟⎥
= ⎮
⋅⎜ ⋅ ⋅
− ⋅ ⋅ +
⋅
⎟
1
EJ
q x
V
q L
M
L
x
A x
A x
d
q x
x q L
.3613 x L
⋅
x
d
⎮
⎣EJ ⎝ 2
⎠⎦
⎮
⌡
EJ ⎝ 2
⎠
⌡
0
0
2
5
⋅L
J =
q
1
0.01719
EJ
L−α⋅L
⌠
L−0.32⋅L
⌠
⎮
⎡
2
⎮
2
1
⎛ 1
2
⎞⎤
1.6666666666666666667 ⎛ 1
2
⎞
I
= ⎮
β⋅ ⋅⎢
⋅⎜ ⋅ ⋅ −
⎟⎥
= ⎮
⋅⎜ ⋅ ⋅
−
⎟
2
EJ
q y
M
y
d
q y
.1387
dy
⎮
⎣β⋅
B
EJ ⎝ 2
⎠⎦
⎮
⌡
EJ
⎝ 2
⎠
⌡
0
0
2
5
− 3
q ⋅L
J =
×
2
9.6901
10
EJ
α⋅L
⌠
0.32⋅L
⌠
⎮
⎡
2
2
1 ⎛ 1
3
1
2
⎞⎤
⎮
2.28 ⎛ 1
3
1
2
⎞
I
= ⎮
(
+ ⋅⎢ ⋅⎜ ⋅ ⋅ − ⋅
⋅ ⋅ ⋅ −
⋅ ⋅ +
⎟⎥
= ⎮
⋅⎜ ⋅ ⋅
− ⋅ ⋅
⋅ +
⋅
⎟
3
1
γ)
q x
V
x q L
M
L
C
x
A
A x
1
d
q x
q x L
.3613 x L
⋅
x
d
⎮
⎣EJ ⎝ 6
2
⎠⎦
⌡
2
⎮
⎝ 6
2
⎠
EJ
0
⌡0
2
7
− 3
q ⋅L
J =
×
3
1.59332
10
2
EJ
L−α⋅L
⌠
L−0.32⋅L
⌠
⎮
⎡
2
2
1
⎛ 1
3
⎞⎤
⎮
2.7777777777777777779 ⎛ 1
3
⎞
I
= ⎮
⎢
⋅⎜ ⋅ ⋅ −
⋅ +
⎟⎥
= ⎮
⋅⎜ ⋅ ⋅
−
⋅ ⎟
4
q y
M
C
dy
q y
.1387 y
y
d
⎮
⎣β⋅
B y
2
EJ ⎝ 6
⎠⎦
⌡
2
⎮
⎝ 6
⎠
EJ
0
⌡0
2
7
− 3
q ⋅L
J =
×
4
2.60749
10
2
EJ
J +
1
J2
EJ
P
=
=
k
6.3989
J +
3
J4
2
L
EJ
P
=
⋅
=
kr
Pk
264.895
kN
2
L
2.3 Wspólczynnik wyboczeniowy π2⋅
μ
EJ
=
μ = 1.24193
2
P ⋅
kr L
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