Sprawozdanie z przedmiotu: Silniki spalinowe

Dobór turbosprężarki do silnika spalinowego o zapłonie samoczynnym 4CT90

Wykonał: Wojciech Darowski

Gr: P1

Dane:

N_doł= 75 [kW]

p_doł= 2 [bar]

Wzór	Wynik	Jednostka
$$S_{\text{td}} = \frac{N_{d}}{N_{e}} = \frac{p_{\text{ed}}}{p_{e}}$$	1,15	[-]
N	23,5	[kW]
$$\pi_{s} = \frac{p_{d}}{p_{1}}$$	2	[-]
$$\varphi_{d} = \frac{\rho_{2}}{\rho_{1}} = \frac{p_{2}}{p_{1}} \bullet \frac{T_{1}}{T_{2}} = \pi_{s} \bullet \frac{1}{1 + \frac{1}{\eta_{iz - s}} \bullet \left( {\pi_{s}}^{\frac{k - 1}{k}} - 1 \right)}$$	1,50	[-]
$\frac{T_{2}}{T_{1}} = \frac{p_{2}}{p_{1}} \bullet \frac{\rho_{1}}{\rho_{2}} = \frac{1}{\varphi_{d}} \bullet \pi_{s}$	1,33	[-]
$$L_{t}^{'} = \frac{100}{23} \bullet \left( \frac{8}{3} \bullet c + 8 \bullet h + s - o \right)$$	14,413	$\mathbf{\lbrack}\frac{\mathbf{\text{kg\ powietrza}}}{\mathbf{\text{kg\ paliwa}}}\mathbf{\rbrack}$
$$\Gamma = \frac{3600 \bullet {\dot{\text{\ m}}}_{s}\ }{N_{d}} = \lambda_{c} \bullet g_{e} \bullet L_{t}^{'} \bullet 10^{- 3\ }$$	7,23	$$\left\lbrack \frac{\mathbf{\text{kg}}}{\mathbf{kW \bullet h}} \right\rbrack$$
$$\rho_{\text{ot}} = \frac{p_{\text{ot}} \bullet \mu_{p}}{\mu \bullet R \bullet T_{\text{ot}}}\ $$	1,184	$$\left\lbrack \frac{\mathbf{\text{kg}}}{\mathbf{m}^{\mathbf{3}}} \right\rbrack$$
$${\dot{m}}_{s} = \frac{\Gamma \bullet N_{d}}{3600}$$	0,1506 19,842	$$\left\lbrack \frac{\mathbf{\text{kg}}}{\mathbf{s}} \right\rbrack$$ [lb/min]
${\dot{V}}_{s} = \frac{\Gamma \bullet N_{d}}{\rho_{\text{ot}} \bullet 3600}\ \left\lbrack \frac{m^{3}}{s} \right\rbrack$	0,12	$\left\lbrack \frac{\mathbf{m}^{\mathbf{3}}}{\mathbf{s}} \right\rbrack$
$T_{2} = T_{1} \bullet \frac{T_{2}}{T_{1}}$	396,34	[K]

Obliczenia sprężarki:

Dobieram turbosprężarkę – GT2056

Obliczenie turbiny

Przyjmuje η_cts=0, 67

Wzór	Wynik	Jednostka
$$\xi = \eta_{\text{cts}} \bullet \frac{T_{3}}{T_{1}} \bullet \frac{{\dot{m}}_{t}}{{\dot{m}}_{s}}$$	1,76	[-]
${\dot{m}}_{t}$=${\dot{m}}_{s}$	0,1506	[kg/s]
$$\pi_{t} = \frac{p_{3}}{p_{4}}$$	1,62	[-]
p4	105	[kPa]
p3 = πt • p4	170,1	[kPa]
T23 = T3 − T2	460	[K]
$$H_{ad - t} = \frac{k_{\text{sp}}}{k_{\text{sp}} - 1} \bullet R_{\text{sp}} \bullet T_{3} \bullet \left\lbrack 1 - \left( \frac{p_{4}}{p_{3}} \right)^{\frac{k_{\text{sp}} - 1}{k_{\text{sp}}}} \right\rbrack$$	97140,32	[-]
ksp	1,34	[-]
Rsp	288,3	$$\left\lbrack \frac{\mathbf{J}}{\mathbf{kg \bullet K}} \right\rbrack$$
$$H_{ad - s} = \frac{k}{k - 1} \bullet R \bullet T_{1} \bullet \left\lbrack \left( \frac{p_{2}}{p_{1}} \right)^{\frac{k - 1}{k}} - 1 \right\rbrack$$		[-]
k	1, 4	[-]
R	287	$$\left\lbrack \frac{\mathbf{J}}{\mathbf{kg \bullet K}} \right\rbrack$$
$$\eta_{\text{cts}} = \frac{H_{ad - s}}{H_{ad - t}}$$	0,67	[-]

Odczytane obroty turbosprężarki wynoszą:

n_t = 140000 [obr/min]

d_t=47 [mm]

Wzrór	Wynik	Jednostka
$$v = \frac{\pi \bullet d_{t} \bullet n_{t}}{60}$$	344,35	$$\left\lbrack \frac{\mathbf{m}}{\mathbf{s}} \right\rbrack$$
$\psi_{t} = \frac{2 \bullet H_{ad - t}}{v_{t}^{2}}$	1,64	[-]
$$\frac{{\dot{m}}_{t} \bullet \sqrt{T_{3}}}{A_{t} \bullet p_{3}} = \sqrt{\frac{2 \bullet k_{\text{sp}}}{k_{\text{sp}} - 1} \bullet \frac{p_{3}}{R_{t}} \bullet \left\lbrack \left( \frac{p_{4}}{p_{3}} \right)^{\frac{2}{k_{\text{sp}}}} - \left( \frac{p_{4}}{p_{3}} \right)^{\frac{k_{\text{sp}} + 1}{k_{\text{sp}}}} \right\rbrack}$$	51,19	[-]