Nr pikiety: 100 (nawiązanie)

x₁₀₀= x_st=150,00

y₁₀₀=y_st+D_st-100

y₁₀₀=150,00+34,087=184,087

Pikieta nr 1

α₁=H_z1-H_z100= 117,0567^g -89,3316^g= 27,7251^g

A_st-1= 100,0000+27,7251= 127,7251^g

Δx_ST-1= D_st-1*cosA_ST-1

Δx_st-1= 8,478*cos127,7251

Δx_st-1= -3,58

Δy_st-1=D_st-1*sinA_ST-1

Δy_st-1=8,478*sin127,7251

Δy_st-1= 7,69

x₁=x_st+ Δx_st-1 → x₁= 146,42

y₁=y_st+ Δy_st-1 → y₁= 157,69

Δh₁=D_st-1/tgV= 8,478/tg102,9473 = -0,393 m

H₁= 171,237+1,465-0,393-1,50

H₁=170,809m

Pikieta nr 2

α₂= H_z2-H_z100=93,6185-89,3316= 4,2869^g

A_st-1=100,0000+4,2869= 104,2869^g

D_st-2= 29,306m

x₂= 150,00+29,306*cos104,2869

y₂=150,00+29,306*sin104,2869

x₂= 148,03

y₂=179,24

Δh₂=29,306/tg99,9865= 0,006

H₂=171,237+1,465+0,006-1,50

H₂=171,208m

Pikieta nr 3

α₃= H_z100-H_z3= 89,3316-80,2344= 9,0972^g

A_st-3=100,0000-9,0972= 90,9028^g

D_st-3=26,173m

x₃=150,00+26,173*cos90,9028

y₃= 150,00+26,173*sin90,9028

x₃=153,73

y₃=175,91

Δh₃=26,173/tg98,9430= 0,434

H₃=171,237+1,465+0,434-1,50

H₃=171,636m

Pikieta nr 4

α₄=H_z100-H_z4= 89,3316-83,1003= 6,2313^g

A_st-4= 100,0000-6,2313= 93,7687^g

D_st-4=13,485m

x₄=150,00+13,485*cos93,7687

y₄=150,00+13,485*sin93,7687

x₄=151,32

y₄=163,42

Δh₄=13,485/tg93,5271=1,376

H₄=171,237+1,465+1,376-1,50

H₄=172,578m

Uniwersytet Zielonogórski

Wydział Inżynierii Lądowej i Środowiska

Kierunek: Budownictwo

SPRAWOZDANIE NR 7

Temat : Tachimetria.