2. Obliczenie krzywych poziomych

Wzory:

-na łuk: T=R*tg$\frac{\alpha}{2}$, D=$\frac{R*\alpha*\pi}{180}$, B=R($\frac{1}{\cos\frac{\alpha}{2}}$-1)

- na krzywe przejściowe: L= $\frac{A^{2}}{R}$ , ζ= $\frac{L}{2R\ }$, γ= α-2*ζ , K= R* γ[rad] , X= L-$\frac{L^{5}}{40*A^{4}\ }$, Y=$\frac{L^{3}}{6*A^{2}}$ , H= Y-R*(1-cos ζ) Xs = X − R * sinζ , To= Xs+T^’ , To= Xs+(R+H)*(tg$\frac{\alpha}{2}$) , X₁=0,25L, X₂=0,5L, X₃=0,75L, X₄=X, Y₁=0,06H, Y₂=0,5H, Y₃=0,423Y, Y₄=Y

a) WARIANT I

W₁=1082,11m W₂=1773,13m

R₁=300,00m R₂=200,00m

α₁=34,73°=0,606rad α₂=19,54°=0,341rad

T₁=93,81m T₂=34,44m

D₁=181,85m D₂=68,21m

B₁=14,33m B₂=2,94m

Dobór parametru A: A_min=60,00m, A_min=$\sqrt{\frac{\text{Vp}^{3}}{{3,6}^{3}*K}}$ , $\frac{1}{3}$R≤A ≤ R , A_max=R*$\sqrt{\propto}$ [rad] , A_max= 2,78*$\sqrt[4]{R^{3}}$ , (A_min= 1,863*$\sqrt[4]{R^{3}}$) , A_min= 1,48*$\sqrt[4]{R^{3}}$

A_1min= 60,00m A_2min= 60,00m

84,44≤A ≤ 250 66,67≤A ≤ 200

A_1max= 194,48m A_2max= 116,70m

A_1min= 57,87m A_2min= 57,87m

A_1max= 174,78m A_2max= 174,78m

(A_1min= 117,13) (A_2min= 117,13)

A_1min= 93,05m A_2min= 93,05m

A₁=109,54m A₂=80,00m

L₁=40,00m L₂=32,00m

A₁=109,54m A₂=80,00m

ζ ₁=0,0667rad=3,82° ζ ₂=0,08rad=4,59°

γ₁=0,473rad=27,11° γ₂=0,181rad=10,37°

K₁=141,90m K₂=36,20m

X₁=39,98m X₂=31,98m

Y₁=0,89m Y₂=0,85m

H₁=0,22m H₂=0,21m

Xs₁=19,99m Xs₂=15,97m

To₁=113,79m To₂=50,43m

X₁= 10m X₁=8m

X₂= 20m X₂= 16m

X₃= 30m X₃=24m

X₄=39,98m X₄=31,98m

Y₁=0,01m Y₁=0,01m

Y₂=0,11m Y₂=0,10m

Y₃=0,38m Y₃=0,36m

Y₄=0,89m Y₄=0,85m

b) WARIANT II

W₃=1113,28m W₄=2726,87m

R₃=250,00m R₄=1050,00m

Α₃=42,44°=0,74rad α₄=17,68° T₃=97,07m T₄=163,30m

D₃=185,18m D₄=324,00m

B₃=18,15m B₄=12,62m

Dobór parametru A: A_min=60,00m, A_min=$\sqrt{\frac{\text{Vp}^{3}}{{3,6}^{3}*K}}$ , $\frac{1}{3}$R≤A ≤ R , A_max=R*$\sqrt{\propto}$ [rad] , A_max= 2,78*$\sqrt[4]{R^{3}}$ , (A_min= 1,863*$\sqrt[4]{R^{3}}$) , A_min= 1,48*$\sqrt[4]{R^{3}}$

A_3min= 60,00m Krzywe przejściowe w tym przypadku nie

100,00≤A ≤ 300, 00 są wymagane.

A_3max= 257,98m

A_3min= 57,87m

A_3max= 200,39m

(A_3min= 134,29m)

A_3min= 106,68m

A₃=100,00m-przyjęta takie A gdyż w tym

Przypadku ważniejsza jest długość L, ze względu

na odległość od skrzyżowania

L₃=40,00m

A₃=100,00m

γ₃=0,08rad=4,59°

γ₃=0,58rad=33,25°

K₃=145,00m

X₃=39,97m

Y₃=1,07m

H₃=0,27m

Xs₃=119,96m

To₃=117,13m

X₁= 10m

X₂= 20m

X₃= 30m

X₄=39,97m

Y₁=0,02m

Y₂=0,13m

Y₃=0,45m

Y₄=1,07m