$$\left( \text{lnx} \right)^{'} = \frac{1}{x}$$

e^x′ = e^x

(a^x)^′ = a^xlna

(a^♡)^′ = a^♡ • lna • ♡′

(e^♡)^′ = e^♡ • ♡′

$$\left( \ln\heartsuit \right)^{'} = \frac{1}{\heartsuit} \bullet \heartsuit'$$

(sin♡)^′ = cos♡•♡′

$$\left( \arccos\heartsuit \right)^{'} = \frac{- 1}{\sqrt{1 - \heartsuit^{2}}} \bullet \heartsuit'$$

(♡^k)′ = k♡^k − 1 • ♡′