12 M1 KazimierczukS NarazińskiM ZAD124

—M_a + 4qa² — 3 aR_B + M_b = O

²    7

^mb = 3^

T(xi)=R_A=^qa

T(x₂) = x₂- q(x₂ ~ a)

T(a)=R_A-0 = ^qa T(3a)=(^- 2)qa = -^qa Max Mg dla T=0:

Ra ~ q(^xi ~ a) = O 16

-q(x₂ - a) = ~ — qa 43

x₂ — — a ^z 27

M(Xi) = R_a-x₁-M_a = ^qa-x₁ ~^qa² M(0 )=-^A-qa²

M(a)=^ qa² - ^A~qa² = ^ qa²

1

M(x₂) = R_a ■ x₂ - M_a - -q(x₂ - a)²

„ _A 16    4,1    ,

M(x₂) = -qa-x₂ - -qa ~~q(x₂ - a)^z

16    4    4

M(.a) = Yj^ąal ~9^{qa2 =} 27^qa2

cnj | m

, _N 16    ,4,1    ,

M(3a) = — ■ 3qa² - - qa² - - ■ 4qa =