dla n>1
0, 1, 1, 2, 3, 5, 8,
13, 21, ...
1
,
0
1
0
F
F
1
2
n
n
n
F
F
F
Function
rfib(n:LongInt):LongInt;
begin
if n=0 then rfib:=0 else
if n=1 then rfib:=1 else
rfib:=rfib(n-2)+rfib(n-
1);
end;
i
x
y
f
0
0
1
2
0
1
0+1=1
3
1
1
1+1=2
4
1
2
1+2=3
5
2
3
2+3=5
6
3
5
3+5=8
7
5
8
5+8=13
Function fib(n:LongInt):LongInt;
var x,y,f,i:LongInt;
begin
if n=0 then f:=0 else
if n=1 then f:=1 else
begin
x:=0; y:=0; f:=1;
for i:=2 to n do
begin
x:=y; y:=f; f:=x+y;
end;
end;
fib:=f;
end;
Program w Pascalu
[F
n+1
, F
n
]=[1, 0]•
n
0
1
1
1
n
n
n
F
2
5
1
2
5
1
5
1
n
n
n
1
5
1
5
n
Wzór
Bineta
1
1
1
1
2
1
1
3
3
1
1
4
6
4
1
1
5
10
10
5
1
1
6
15
20
15
6
1
1
7
21
35
35
21
7
1
1
8
28
56
70
56
28
8
1
1
1
2
3
5
8
13
21
34
Trójkąt
Pascala
2
/
0
1
n
k
n
k
k
n
F
2
/
)
1
(
0
1
1
2
5
2
1
n
k
n
n
n
k
n
F
1
lim
n
n
n
F
F
1
1
1
1
1
n
n
n
n
F
F
n
n
n
n
F
F
F
1
2
1
1
1
2
1
1
2
4
n
n
n
n
n
F
F
F
F
F
n
k
n
k
F
F
k
n
2
0
n
k
k
n
k
F
F
k
n
3
0
2