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Sito mm |
Wartości przesiewu krzywych granicznych |
Zawartość piasku |
zawartość kruszywa |
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dolna |
górna |
0--2 |
4--8 |
8--16 |
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% |
% |
% |
% |
% |
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0 |
0 |
0 |
0 |
0 |
0 |
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0,125 |
0 |
5 |
2,99 |
0 |
0 |
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0,25 |
2 |
10 |
19,45 |
0 |
0 |
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0,5 |
8 |
20 |
79,3 |
0 |
0 |
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1 |
18 |
35 |
98,75 |
0 |
0 |
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2 |
25 |
50 |
99,5 |
0 |
0 |
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4 |
30 |
60 |
0 |
100 |
0 |
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8 |
50 |
80 |
0 |
0 |
100 |
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16 |
100 |
100 |
0 |
0 |
0 |
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piasek = 40% (dla sita max 2mm) |
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kruszywo |
udział w [%] |
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piasek |
25 |
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4--8 |
30 |
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8--16 |
45 |
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razem |
100 |
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Sito mm |
Wartości przesiewu krzywych granicznych |
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górna "1" |
środkowa "2" |
dolna "3" |
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% |
% |
% |
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0 |
0 |
0 |
0 |
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0,125 |
10 |
2 |
0 |
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0,25 |
25 |
5 |
0 |
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0,5 |
60 |
30 |
0 |
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1 |
80 |
60 |
30 |
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2 |
100 |
100 |
100 |
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ćwiczenia 15,05,10 |
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wyznaczenie wodożądności optymalnego składu ziarnowego kruszywa |
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wodożądnosć piasku = |
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0,0944 |
dm3/kg |
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wodożądnosc 4-8= |
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0,027 |
dm3/kg |
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wodożądność 8-16= |
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0,022 |
dm3/kg |
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wodożądność dobranego kruszywa (mieszanki kruszywa) |
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0,0416 |
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wyznaczenie gęstości kruszywa do betonu |
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gestość piasku= |
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2,65 |
kg/dm3 |
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bazalt = |
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2,85 |
kg/dm3 |
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bazalt 8-16 = |
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2,85 |
kg/dm3 |
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gęstość kruszywa do betonu = |
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2,8 |
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Ustalenie składu ilościowego mieszanki betonowej metodą trzech równań. |
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Równania |
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fcmp = A(C/W- 0,5) |
Warunek wytrzymałości |
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W= K * Wk + C * Wc |
Warunek konsystencji |
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1000= C/ρc + K/ρk + W |
Warunek szczelnośći |
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Legenda: |
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fcmp - projektowana wytrzymałość na ścisknie betonu |
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K1 |
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Wk, Wc - wodożądność kruszywa i cementu |
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C,W,K - ilość cementu kruszywa i wody w kg/m3 |
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ρc, ρk - gęstości kruszywa i cementu |
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A - wskaźnik jakości kruszywa i cementu, zależny od rodzaju kruszywa i klasy cementu |
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Dane |
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fcmp |
42 |
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A |
24 |
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Wyznaczenie projektowanej wytrzymałości betonu na ściskanie |
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wk |
0,0416 |
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Projektowana klasa wytrzymałości betonu - |
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wc |
0,27 |
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Wytrzymałość charakterystyczna projektowanego betonu - fck = |
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ρc |
3,1 |
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fcmp = fck + 12 MPa = |
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ρk |
2,8 |
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wytrzymałość betonu będzie sprawdzana na próbkach walcowych |
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Równania przekształcone |
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Co= 1000/B * [( fcmp/A) + 0,5)] |
441,567504638794 |
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Wo= 1000/B |
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196,252224283908 |
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Ko= 1000/B * 1/Wk * {1- Wc*[(fcmp/A) + 0,5)} |
1851,65860652486 |
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Wyliczyć wartość B |
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2489,47833544756 |
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B= 1 + 1/(Wk * ρk) - [(fcmp/A) + 0,5) * (Wc/(Wk *ρk) - 1/ρc) |
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B= |
5,095 |
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Wyliczyć podane poniżej wartości |
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C0= |
441,568 |
kg/m3 |
|
sprawdzenie |
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W0= |
196,252 |
kg/m3 |
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K0= |
1851,659 |
kg/m3 |
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piasek |
462,915 |
kg/m3 |
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1000= C/ρc + K/ρk + W |
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4--8 |
555,498 |
kg/m3 |
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1000= |
1000 |
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8--16 |
833,246 |
kg/m3 |
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razem kruszywo |
1851,659 |
kg/m3 |
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uwaga zmieniamy klasę cementu przyjmując A=24 |
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po sprawdzac reszta na następnych zajęciach |
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Ćwiczenia 30 maj 2010 |
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Sprawdzenie parametrów mieszanki betonowej |
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1. Wykonanie próbnego zarobu w ilości 12 dm3 |
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Recepta na 12 dm3 |
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C1 |
5,299 |
kg |
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W1 |
2,355 |
kg |
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K1 |
22,220 |
kg |
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w tym: |
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piasek |
5,555 |
kg |
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4--8 |
6,666 |
kg |
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8--16 |
9,999 |
kg |
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suma kruszywa |
22,220 |
kg |
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(wstawić treść informacji zawarych w pliku worda "konsystencja") |
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2. Sprawdzenie konsystencji mieszanki betonowej |
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Projektowana konsystencja |
S3 |
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Metoda badania - |
opad stożka |
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Wymagania normowe |
100-150 mm |
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Wynik badania |
110 mm |
Konsystencja - |
plastyczna |
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Korekta wody |
zostalo 0,1 dm3 wody |
9,09090909090909 |
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Korekta składu mieszanki betonowej uwzględniająca rzeczywistą ilość wody |
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Rzeczywista objętność próbnego zarobu = 12 dm3 - korekta wody =12-0,2dm3=11,8dm3 |
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Recepta po korekcie wody: |
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C2= |
486,1 |
kg/m3 |
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Wyliczyć podane poniżej wartości |
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W2= |
206,9 |
kg/m3 |
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C0= |
441,567504638794 |
kg/m3 |
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K2= |
2038,5 |
kg/m3 |
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W0= |
196,252224283908 |
kg/m3 |
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w tym: |
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K0= |
1851,65860652486 |
kg/m3 |
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piasek |
509,6 |
kg/m3 |
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piasek |
462,914651631214 |
kg/m3 |
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4--8 |
611,6 |
kg/m3 |
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4--8 |
555,497581957457 |
kg/m3 |
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8--16 |
917,3 |
kg/m3 |
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8--16 |
833,246372936185 |
kg/m3 |
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suma |
2038,5 |
kg/m3 |
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|
1851,65860652486 |
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3. Sprawdzenie zawartości powietrza w mieszance betonowej |
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a) Metoda badania- bezpośrednia, metoda ciśnieniowa |
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b) Dopuszczalna zawartość powietrza w mieszance betonowej <2% (wg. PN-88/B-06250) |
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c)Wynik badania |
1,60% |
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Objetość powietrza w 1m3 mieszanki betonowej wynosi |
16 |
dm3 |
powietrza |
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Objetość rzeczywista mieszanki betonowej wynosi: |
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1000+15= |
1016 |
dm3 |
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Koretkta składu mieszanki betonowej uwzględniająca powietrze: |
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C3= |
478,5 |
kg/m3 |
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W3= |
203,6 |
kg/m3 |
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K3= |
2006,4 |
kg/m3 |
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w tym: |
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piasek |
501,6 |
kg/m3 |
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4--8 |
601,9 |
kg/m3 |
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8--16 |
902,9 |
kg/m3 |
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2006,4 |
kg/m3 |
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4. Ocena klasy wytrzymałości betonu |
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Rodzaj probki- szescian o boku 150 mm |
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Ilość próbek- 3 sztuki |
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Data formowania próbek - |
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Wyniki badań wytrzymałości na ściskanie betonu |
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Nr próbki |
P |
F |
fci |
fcm |
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kN |
cm2 |
MPa |
MPa |
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1 próbka |
950 |
225 |
42,1 |
42,23 |
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2 próbka |
940 |
225 |
41,9 |
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3 próbka |
965 |
225 |
42,7 |
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42,2333333333333 |
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P- siła niszczaca |
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F- powierzchnia próbki |
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fci- wytrzymałość na ściskanie próbek |
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fcm-średnia wytrzymałość na ściskanie |
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Ocena klasy betonu wg. PN-EN 206-1 |
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Jezeli beton jest określonej klasy to jego wytrzymalość na ścisakanie powinna spełniać dwa kryteria równoczesnie (dla liczby badań - 3) |
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Kryterium 1 |
fcm>=fck cube + 4 |
Warunek spełniony |
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42,3>=37+4=41 |
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Kryterium 2 |
fci>=fck cube - 4 |
Warunek spełniony |
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41,7>=37-4=33 |
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fcm- średnia wytrzymałośc na ściskanie n wyników (MPa) |
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fci- dowolny pojedynczy wynik badania (MPa) |
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fck cube= 37 |
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Wynika z klasy projektowanego betonu |
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Wniosek:Podana w projekcie recepta pozwala na uzyskanie wymaganego betonu C30/37 |
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IV. Recepta robocza |
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Uwzględnienie wilgotności kruszywa |
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Wilgotność (G): |
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piasek |
5 |
% |
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grube |
3 |
% |
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Recepta po korekcie powietrza |
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C3= |
478,5 |
kg/m3 |
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W3= |
203,6 |
kg/m3 |
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K3= |
2006,4 |
kg/m3 |
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w tym: |
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piasek= |
501,6 |
kg/m3 |
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Masa suchego piasku |
501,605 |
kg/m3 |
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kruszywo grube |
1504,8 |
kg/m3 |
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Masa suchego wapienia |
1504,815 |
kg/m3 |
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razem kruszywo |
2006,4 |
kg/m3 |
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razem kruszywo |
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2006,421 |
kg/m3 |
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G=(masa wilgotnego kruszywa- masa suchego kruszywa/masa suchego kruszywa)*100 |
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0 |
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Woda wprowadzona przez wilgotny piasek = |
25,1 |
kg/m3 |
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Woda wprowadzona przez wilgotne kruszywo = |
45,1 |
kg/m3 |
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Masa wody wprowadzana przez kruszywo........ = |
70,2 |
kg/m3 |
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Masa wilgotnego piasku = |
526,7 |
kg/m3 |
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Masa wilgotmego ........... = |
1550,0 |
kg/m3 |
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Recepta uwzględniająga wilgotność kruszywa |
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Cement |
C4 |
478,5 |
kg/m3 |
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Woda |
W4 |
133,4 |
kg/m3 |
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Kruszywo |
K4 |
2076,6 |
kg/m3 |
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w tym: |
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piasek |
519,2 |
kg/m3 |
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4--8 |
623,0 |
kg/m3 |
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8--16 |
934,5 |
kg/m3 |
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suma |
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2076,6 |
kg/m3 |
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osobne ćiwczenie |
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Miejsce |
Kąt |
Odczyt L |
Odczyt średni |
Odchylenie standardowe., sl |
Współcz. zmienności, vl |
α |
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Lia |
1,00 |
-90,00 |
44,60 |
42,80 |
46,30 |
42,20 |
44,90 |
45,20 |
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44,33 |
1,544 |
0,035 |
2,00 |
0o |
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4,50 |
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3,00 |
0o |
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wiek betonu: ...... dni, stan wilgotności: powietrznosuchy Σ |
48,83 |
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6 |
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przepisać wzory z młotka szmita |
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L= |
7,38888888888889 |
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47,323 |
MPa |
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