R[1-5,7-10] =
=
= 9 Ω

I =
= 2 A

P = 18 V ∙ 2 A = 36 W

	R1 = 36 Ω R2 = 1 Ω R3 = 3 Ω R4 = 10 Ω R5 = 7 Ω R6 = 5 Ω R7 = 10 Ω R8 = 6 Ω R9 = 4 Ω R10 = 1 Ω E = 18 V
	R[3,5] = 3 + 7 = 10 Ω R[8,9] = 6 + 4 = 10 Ω
	Z braku różnicy potencjałów, przez opornik R6 nie popłynie prąd.
	R[4,7] = 10 + 10 = 20 Ω R[3,5,8,9] = 10 + 10 = 20 Ω
	R[3-5,7-9] = = = 10 Ω
	R[2-5,7-10] = 1 + 10 + 1 = 12 Ω

Łukasz Grobelny

ZADANIE 5

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