II OBLICZENIA

1.

$$\mathbf{R =}\frac{\mathbf{n}^{\mathbf{2}}\mathbf{- 1}}{\mathbf{n}^{\mathbf{2}}\mathbf{+ 2}}\mathbf{*}\frac{\mathbf{M}}{\mathbf{d}}\mathbf{\ }\left\lbrack \frac{\mathbf{\text{cm}}^{\mathbf{3}}}{\mathbf{\text{mol}}} \right\rbrack$$

$$R_{dosw.1} = \frac{{(1,357)}^{2} - 1}{{(1,357)}^{2} + 2}*\frac{72}{0,626} = \frac{0,841449}{3,841449}*115,0159744 = 25,1936\left\lbrack \frac{\text{cm}^{3}}{\text{mol}} \right\rbrack$$

$$R_{dosw.2} = 29,8865\left\lbrack \frac{\text{cm}^{3}}{\text{mol}} \right\rbrack$$

$$R_{dosw.3} = 34,5186\left\lbrack \frac{\text{cm}^{3}}{\text{mol}} \right\rbrack$$

Ciecz nr 1-pentan C₅H₁₂

Ciecz nr 2-heksan C₆H₁₄

Ciecz nr 3- heptan C₇H₁₆

$$d_{1} = 0,626\left\lbrack \frac{g}{\text{cm}^{3}} \right\rbrack$$

$$d_{2} = 0,6295\ \left\lbrack \frac{g}{\text{cm}^{3}} \right\rbrack$$

$$d_{3} = 0,6836\ \left\lbrack \frac{g}{\text{cm}^{3}} \right\rbrack$$

$$M_{1} = 72\left\lbrack \frac{g}{\text{mol}} \right\rbrack$$

$$M_{2} = 86\left\lbrack \frac{g}{\text{mol}} \right\rbrack$$

$$M_{3} = 100\left\lbrack \frac{g}{\text{mol}} \right\rbrack$$

n₁ = 1, 357

n₂ = 1, 376

n₃ = 1, 388

R_teoret.1 = 5 * 2, 418 + 12 * 1, 100 = 25, 29

R_teoret.2 = 29, 908

R_teoret.3 = 34, 526

2.

$\mathbf{Cp =}\frac{\mathbf{m}_{\mathbf{s}}}{\mathbf{m}_{\mathbf{r - r}}}\mathbf{*100\%}$

m_s=15[g]

m_r − r=146,73-39,12=107,61[g]

$$Cp = \frac{15}{107,61}*100\% = 13,939\%$$

$$\mathbf{d}_{\mathbf{r - r}}\mathbf{=}\frac{\mathbf{m}_{\mathbf{r - r}}}{\mathbf{V}_{\mathbf{r - r}}}$$

m = 82, 36 − 25, 24 = 57, 12[g]

V_r − r = 50cm³

$$d_{r - r} = \frac{57,12}{50}1,1424\left\lbrack \frac{g}{\text{cm}^{3}} \right\rbrack$$

$$\mathbf{r}_{\mathbf{wl}}\mathbf{=}\frac{\mathbf{n}^{\mathbf{2}}\mathbf{- 1}}{\mathbf{n}^{\mathbf{2}}\mathbf{+ 2}}\mathbf{*}\frac{\mathbf{1}}{\mathbf{d}}$$

n_wody = 1, 333

n_roztw. = 1, 357

$$d_{\text{wody}} = 0,9982\left\lbrack \frac{g}{\text{cm}^{3}} \right\rbrack$$

$$r_{wl\text{.wody}} = \frac{{(1,333)}^{2} - 1}{{(1,333)}^{2} + 2}*\frac{1}{0,9982} = \frac{0,776889}{3,776889}*\frac{1}{0,9982} = 0,2061\left\lbrack \frac{1}{\text{cm}^{3}} \right\rbrack$$

$$r_{wl.roztw.} = 0,1917\left\lbrack \frac{1}{\text{cm}^{3}} \right\rbrack$$

$$\mathbf{r}_{\mathbf{\text{NaCl}}}\mathbf{=}\frac{\mathbf{100*}\mathbf{r}_{\mathbf{wl.roztw.}}\mathbf{-}\left( \mathbf{100 - Cp} \right)\mathbf{*}\mathbf{r}_{\mathbf{wl.wody}}}{\mathbf{\text{Cp}}}$$

$$r_{\text{NaCl}} = \frac{100*0,1917 - \left( 100 - 13,939 \right)*0,2061}{13,939} = 0,1033$$

3.

$$\mathbf{p =}\frac{\mathbf{100*(}\mathbf{r}_{\mathbf{wl.\ roztw.}}\mathbf{-}\mathbf{r}_{\mathbf{wl.wody}}\mathbf{)}}{\mathbf{r}_{\mathbf{\text{NaCl}}}\mathbf{-}\mathbf{r}_{\mathbf{wl.wody}}}\left\lbrack \mathbf{\%} \right\rbrack$$

$$p = \frac{100*(0,1917 - 0,2061)}{0,1033 - 0,2061} = 13,939\lbrack\%\rbrack$$