MECHANIKA LOTU
PROJEKT 5
,,CHARAKTERYSTYKI ZESPOŁU NAPĘDOWEGO’’
WYKONAŁ : KAROL WŁOSIK 187220
DATA ODDANIA: 15.01.2015
V.1 Dane potrzebne do obliczeń :
$$\mathbf{V}_{\mathbf{d}}\mathbf{=}\mathbf{500}\frac{\mathbf{\text{km}}}{\mathbf{h}}\mathbf{=}\mathbf{1}\mathbf{38,88}\frac{\mathbf{m}}{\mathbf{s}}$$
hd=6000m
N(0)=1412 kW
ns(0)= 40 obr/s
Nsd= 973, 38 kW
nsd=27, 6 obr/s
V.2 Obliczenie cechy bezśrednicowej śmigła Cd
Gęstość powietrza na wysokości hd=6000 m :
$$\mathbf{\rho}_{\mathbf{d}}\mathbf{= 1,225}{\mathbf{(1 -}\frac{\mathbf{6000}}{\mathbf{44331}}\mathbf{)}}^{\mathbf{4,256}}\mathbf{= 0,}\mathbf{659}\frac{\mathbf{\text{kg}}}{\mathbf{m}^{\mathbf{3}}}$$
$$\mathbf{C}_{\mathbf{d}}\mathbf{=}\mathbf{V}_{\mathbf{d}}\mathbf{*}\sqrt[\mathbf{5}]{\frac{\mathbf{\rho}_{\mathbf{d}}}{\mathbf{N}_{\mathbf{d}}\left( \mathbf{n}_{\mathbf{\text{sd}}} \right)^{\mathbf{2}}}}\mathbf{=}\mathbf{1}\mathbf{38,88}\mathbf{*}\sqrt[\mathbf{5}]{\frac{\mathbf{0,659}}{\mathbf{973,38}\mathbf{*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\mathbf{27,6}^{\mathbf{2}}}}\mathbf{=}\mathbf{2,}\mathbf{14}$$
Dla obliczonej wartości cechy bezśrednicowej śmigła dobieram śmigło 3-ramienne 5868-g o profilu typu Clark Y.
V.3 Obliczenie średnicy śmigła
$$\mathbf{D =}\frac{\mathbf{V}_{\mathbf{d}}}{\mathbf{J*}\mathbf{n}_{\mathbf{\text{sd}}}}$$
Parametr J dobieram do obliczeń z wykresu dla kąta nastawienia łopat β, przy którym wartość sprawności jest największa. Jest to kąt β=45°.
Vd=138,88 m/s
J=1,75 , zatem :
$$\mathbf{D =}\frac{\mathbf{V}_{\mathbf{d}}}{\mathbf{J*}\mathbf{n}_{\mathbf{\text{sd}}}}\mathbf{=}\frac{\mathbf{138,88}}{\mathbf{1,}\mathbf{75}\mathbf{*}\mathbf{2}\mathbf{7}\mathbf{,}\mathbf{6}}\mathbf{=}\mathbf{2,}\mathbf{87}\mathbf{\text{\ m}}$$
V.4 Sprawdzenie liczby Macha na końcu łopaty śmigła
Dla H=6000m add=316,3m/s
Vmax=1,2Vd=166,65m/s
$$\mathbf{\text{Ma}}_{\mathbf{\text{kl}}}\mathbf{=}\frac{\sqrt{\mathbf{V}_{\mathbf{\max}}^{\mathbf{2}}\mathbf{+}{\mathbf{(\pi*}\mathbf{n}_{\mathbf{\text{sd}}}\mathbf{*D)}}^{\mathbf{2}}}}{\mathbf{a}_{\mathbf{\text{dd}}}}\mathbf{=}\frac{\sqrt{\mathbf{166,65}^{\mathbf{2}}\mathbf{+}{\mathbf{(\pi*}\mathbf{27,6}\mathbf{*}\mathbf{2,}\mathbf{87}\mathbf{)}}^{\mathbf{2}}}}{\mathbf{316}}\mathbf{=}\mathbf{0,}\mathbf{94}$$
V.5 Wyznaczenie mocy rozporządzalnej
Nr=N*ηs
h,m | ρ, kg/m3 |
---|---|
0 | 1,225 |
1000 | 1,111 |
2000 | 1,006486 |
3000 | 0,909115 |
4000 | 0,819122 |
5000 | 0,736107 |
6000 | 0,659688 |
8000 | 0,525157 |
$\mathbf{N}\left( \mathbf{h = 8000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{0,525}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{= 849,27*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$
nsh = 8000=24, 1 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{=}\mathbf{0,593}\mathbf{5}$$
$\mathbf{N}\left( \mathbf{h = 6000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{0,659}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{= 973,38*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$
nsh = 6000=27, 6 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{=}\mathbf{0,3}\mathbf{60}\mathbf{7}$$
$$\mathbf{C.)}\mathbf{N}\left( \mathbf{h =}\mathbf{5}\mathbf{000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{0,}\mathbf{736}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{=}\mathbf{1040,11}\mathbf{*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$$
nsh = 6000=29,4 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{2838}$$
$$\mathbf{D.)}\mathbf{N}\left( \mathbf{h = 4000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{0,819}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{= 1108,97*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$$
nsh = 4000=31, 4 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{2}\mathbf{246}$$
$$\mathbf{E.)N}\left( \mathbf{h = 3000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{0,909}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{= 1180,56*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$$
nsh=3000=33, 4 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{173}\mathbf{8}$$
$$\mathbf{F}\mathbf{.)}\mathbf{N}\left( \mathbf{h = 2000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{1,006}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{= 1254,61*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$$
nsh = 2000=35, 5 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{1431}$$
G.)$\mathbf{N}\mathbf{\ }\left( \mathbf{h = 1000}\mathbf{m} \right)\mathbf{= N}\left( \mathbf{h = 0}\mathbf{m} \right)\mathbf{*}\left( \frac{\mathbf{\rho}}{\mathbf{\rho}_{\mathbf{0}}} \right)^{\mathbf{0,6}}\mathbf{= 1412*}\mathbf{10}^{\mathbf{3}}\mathbf{*}\left( \frac{\mathbf{1,}\mathbf{111}}{\mathbf{1,225}} \right)^{\mathbf{0,6}}\mathbf{=}\mathbf{1331,62}\mathbf{*\ }\mathbf{10}^{\mathbf{3}}\mathbf{\text{\ W}}$
nsh = 2000=37, 5 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{1}\mathbf{167}$$
G.) (h=0m)
N(0)=1412 kW
ns(0)= 40 obr/s
$$\mathbf{C}_{\mathbf{N}}\mathbf{=}\frac{\mathbf{N}}{\mathbf{\rho*}{\mathbf{\eta}_{\mathbf{\text{sd}}}}^{\mathbf{3}}\mathbf{*}\mathbf{D}^{\mathbf{5}}}\mathbf{= 0,}\mathbf{092}\mathbf{4}$$
h=0m |
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L.p. |
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2 |
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7 |
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h1=1000 m |
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L.p. |
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h2=2000 m |
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L.p. |
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h3=3 000 m |
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L.p. |
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h4=4000 m |
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L.p. |
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h5=5000 m |
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L.p. |
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h6=6 000 m |
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L.p. |
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h7=8000 m |
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L.p. |
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8 |