x-4
x-4
~dx — /
B _ x(A + B)-3A~2B
(x-2)(x-3) x — 2 x-3
/4 = 2
(x-2Xx-3)
.4 + 5 = 1 -3/1-25 =-4 dx
B = -1
r 2x + 7 , r ZX +1 + O , r ZX+ l , r
I—-dr = I—-<&= i—-dx +
•*x"+x —2 3r' + r —2 ■'x2 + x-2 J
1 x +x-2
r 2x + 1 + 6
—=-1
’x2 + x-2
2x + l x2 +x-2
6dx
1 x2 + x- 2
'= J—T + J—-.-2ln|, + 2|+2ln|»-!|+c
J
= In|x2 +x-2| + /
6 /I 5 x(/l + 5)-/l + 25
x:+x-2 x + 2 x — 1 (x + 2X*~l)
A + B = 0 JA=—2
-A + 2B = 6 [5 = 2
r- 2dx r 2<&
x + 2 Jx-1 Y~+ ^ = ln|x2 + x-2|-2In|x + 2|+21n|x-l| + C
3x2 + 2x-3
x3-x
3x -1 + 2x- 2 x(x-l)
: r3x‘ -1 r 2x
J——<*+hr
J x -x J xlx
2x-2
V7-*/
dx
= ln|x3 -x| + 2 J-
x(x +1)
ln x - x + /
_1_=A+_B_ = x(A + B)+ A
x(x + l) X x + l x(x + l)
\A+B = 0 j A = \
[ A = 1 [5 = -l
3x2 + 2x - 3
dx- ln|x3 -x|+2ln|x|-21n|x + l|+C
m J^^=(x+4+5^}&=y+4x+I^r7dr=T+4x+/
7x +1 7x + l /< | 5 _x(,4+5)-5
(
x(x-l) X x-l x(x-l) A + B = 7 { A = &
-5=1 |5 = -|
/=J~“f7rr=8lnN-lnk-,l+c
J%^^ = ^- + 4x-8ln|x|-ln|x-l| + C
dr
= /
\'X XA + XB Cx + D x\A + C)-x'(A-B-D)+x{A-B)+B
\ i i . 77 ł n "
x3(x3-x + l) x x3 x3-x+l
3(x3 -x + l)
A + C = O -/4 + 5+D = 0 A-B = 0 5 = 1
t£c r<Ar
-4 = 1 5 = 1
C = -l 0 = 0 xdx
l = f« + J - = ln|x|--—/,
J X Jx2 Jx3-x + l 11 X
.<-3
1 1
J f = f 2 + 3A=l ęyji4fT^--^-xłi4f
J r2 — r+1 •'r2 —r + 1 2^x3 — X + 1 2 ^ —X+1 2 2^1
dx
J.t2-x+l x* —x+l 2-*x3-x+1 2-’x3-x+1 2
= | ln|x3 - x + J| + +C
/ = ln|x| - ^ ^ ln|x3 - x +1| - -y arctg + C
H)
x-2 = / dx-dt x=t+2
= J^±^=|2^9a = 2J^+9J^ = 21lł)_?+c
-25-