p43 073

background image

73.

(a) Following Sample Problem 43-10, we compute

E

¯

h

t

avg

=

(4.14

× 10

15

eV

·fs)/2π

1.0

× 10

22

s

= 6.6

× 10

6

eV .

(b) In order to fully distribute the energy in a fairly large nucleus, and create a “compound nucleus”

equilibrium configuration, about 10

15

s is typically required. A reaction state that exists no more

than about 10

22

s does not qualify as a compound nucleus.


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