zob. Wytrzymałość Materiałów, E.Bielewicz - Przykład 9.2, str. 147...
	E=	2,1 . (10^5) [M Pa]	2,1000E+08	[kN/m2]
	J=	336 400 [cm4]	3,3640E-03	[m4]
	L=	6 [m]	6,0000E+00	[m]
(x,y)	EJy=	-(Pn.an'/6.L).(x)^3+C1.(x)+C2
(x',y')	EJy'=	-(Pn.an/6.L).(x')^3+C3.(x')+C4
	C1=	[(Pn .an.an')/(6.L)].(2.an+an')
	C2=	0
	C3=	[(Pn .an.an')/(6.L)].(2.an'+an)					w pole oznaczone tym kolorem
	C4=	0					wpisz dane
x=	a1=	(L/2)	3,0000E+00	[m]		a2=a1=	3,0000E+00	[m]
3	C1=C3=	[Pn.(L)^2]/16
	EJy=	-(Pn/12).(x)^3+{[Pn.(L)^2]/16}.(x)
	P1=		0,0000E+00	[kN]		P2=	0,0000E+00	[kN]
	d1=		0,0000E+00	[m]		d2=	0,0000E+00	[m]
	Lz1=Ep1=	(1/2).{SUM[(Pn_i).(dn_i)]}	0,0000E+00	[kNm]		Lz2=Ep2=	0,0000E+00	[kNm]
		skutek od przyczyny = SUMA sił					SUMA (sił, przemieszczeń, prac/energii)
	Suma P=	(P1+P2)	0,0000E+00	[kN]			0,0000E+00	[kN]
	Suma d=	d(P1+P2) < = ? = > d1+d2	0,0000E+00	[m]			0,0000E+00	[m]
	LzS=EpS=	(1/2).{SUM[(Pn_i).(dn_i)]}	0,0000E+00	[kNm]		!!!	0,0000E+00	[kNm]