długość boków dna zbiornika |
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Obliczenia |
shz2 |
(p+1) |
s2hz4 |
(p2+2p+1) |
16/3 s2hz4p |
4hzpVN |
2phz |
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wyniki |
2,94 |
2,5 |
8,6436 |
6,25 |
69,1488 |
2318,4 |
4,2 |
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x = |
9,68 |
[m] |
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x = |
9,67676994730232 |
[m] |
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VN= |
276,000 |
[m3] |
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y= |
14,5151549209535 |
[m] |
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gdzie: |
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gdzie: |
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x – długość pierwszego boku podstawy zbiornika |
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Dane: |
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y – długość drugiego boku podstawy zbiornika |
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s – 1:s tj. pochylenie skarpy |
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s |
1,5 |
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x – długość pierwszego boku podstawy zbiornika |
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hz – głębokość wypełnienia zbiornika [m] |
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hz |
1,4 |
[m] |
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p – 1:p stosunek długości boków dna zbiornika |
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p – 1:p stosunek długości boków dna zbiornika |
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p |
1,5 |
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VN – objętość napełnienia zbiornika |
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Z |
92,0000 |
[m3] |
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Z – dzienne zapotrzebowanie na wodę |
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całkowita głębokość zbiornika retencyjnego |
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H= |
1,75 |
[m] |
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gdzie: |
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Dane: |
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Hz – całkowita głębokość zbiornika [m] |
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hz |
1,4 |
[m] |
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hz – głębokość wypełnienia zbiornika [m] |
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hr |
0,35 |
[m] |
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hr – całkowita głębokość rowu doprowadzającego [m] |
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wymiary zbiornika na powierzchni gruntu |
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X= |
14,93 |
[m] |
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gdzie: |
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X – długość pierwszego boku zbiornika na powierzchni gruntu |
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Dane: |
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x – długość pierwszego boku podstawy zbiornika |
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x |
9,67676994730232 |
[m] |
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s – 1:s tj. pochylenie skarpy |
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s |
1,5 |
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Hz – całkowita głębokość zbiornika [m] |
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Hz |
1,75 |
[m] |
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Y= |
19,77 |
[m] |
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gdzie: |
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Dane: |
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Y – długość drugiego boku zbiornika na powierzchni gruntu |
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y |
14,5151549209535 |
[m] |
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y – długość drugiego boku podstawy zbiornika |
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s |
1,5 |
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s – 1:s tj. pochylenie skarpy |
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Hz |
1,75 |
[m] |
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Hz – całkowita głębokość zbiornika [m] |
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rów - wymagany przepływ [m3/s] |
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Qw = |
0,0128 |
[m3/s] |
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gdzie: |
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Dane: |
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Qw – wymagany przepływ w ciągu 24h |
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VN |
276 |
[m] |
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VN – objętość napełnienia zbiornika |
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t |
21600 |
[s] |
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t – czas |
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obliczenie przepływu wody w rowie |
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gdzie: |
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Dane: |
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F – pole przekroju napełnionego wodą [m2] |
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s |
1,5 |
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v – średnia prędkość wody w rowie [m/s] |
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hwr |
0,10 |
[m] |
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a – szerokość dna rowu [m] |
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I |
0,6 |
[‰] |
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b – szerokość rowu na wysokości wypełnienia wodą [m] |
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n |
0,025 |
[m⅓/s] |
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s – 1:s tj. pochylenie skarpy rowu |
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I |
0,0006 |
[niemianowana] |
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hwr – głębokość wypełnienia rowu [m] |
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c – współczynnik prędkości przepływu [m½/s] |
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I – spadek dna rowu [niemianowany] |
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R – promień hydrauliczny [m] |
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n – współczynnik szorstkości koryta [m⅓/s] |
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0,637302761679696 |
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O – obwód zwilżony |
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d – długość skarpy od dna do wysokości wypełnienia wodą |
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pierwszy ciąg obliczeń |
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założone a |
0,60 |
[m] |
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d = |
0,1803 |
[m] |
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O = |
0,9606 |
[m] |
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b = |
0,9000 |
[m] |
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F = |
0,0750 |
[m2] |
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R = |
0,0781 |
[m] |
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c = |
26,1506900202551 |
[m½/s] |
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v = |
0,1790 |
[m/s] |
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Q = |
0,0134 |
[m3/s] |
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drugi ciąg obliczeń |
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jeżeli dla a = |
0,57 |
[m] Q = |
0,01342 |
[m] |
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to a powinno wynosić: |
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a = |
0,57 |
[m] |
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d = |
0,1803 |
[m] |
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O = |
0,9306 |
[m] |
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b = |
0,8700 |
[m] |
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F = |
0,0720 |
[m2] |
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R = |
0,0773732 |
[m] |
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c = |
26,1110932835177 |
[m½/s] |
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v = |
0,1779 |
[m/s] |
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Q = |
0,01281 |
[m3/s] |
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Qw = |
0,0128 |
[m3/s] |
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szerokość rowu na powierzchni gruntu |
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A = |
1,62 |
[m] |
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gdzie: |
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Dane: |
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A – szerokość rowu na powierzchni gruntu [m] |
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s |
1,5 |
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a – szerokość dna rowu [m] |
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a |
0,57 |
[m] |
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s – 1:s tj. pochylenie skarpy rowu |
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hr |
0,35 |
[m] |
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hr – całkowita głębokość rowu doprowadzającego [m] |
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