INSTYTUT GEODEZJI OLSZTYN 30.03.1999r.

SPRAWOZDANIE NR 3

TEMAT: METODA ŚREDNIEJ SZEROKOŚCI GAUSSA.

WYKONAŁ:

Marcin L. Czajkowski

Dane:

B1 = 53° 30' 24'',6660 = (stopnie w systemie dziesiętnym) = 53,50685167

L1 = 20° 30' 57'',0796 = (stopnie w systemie dziesiętnym) = 20,51585544

B2 = 53° 42' 32'',4144 = (stopnie w systemie dziesiętnym) = 53,709004

L2 = 20° 30' 59'',5427 = (stopnie w systemie dziesiętnym) = 20,51653964

B3 = 53° 42' 36'',9498 = (stopnie w systemie dziesiętnym) = 53,71026383

L3 = 20° 46' 04'',4179 = (stopnie w systemie dziesiętnym) = 20,76789386

B4 = 53° 30' 23'',3483 = (stopnie w systemie dziesiętnym) = 53,50648564

L4 = 20° 45' 52'',9953 = (stopnie w systemie dziesiętnym) = 20,76472092

a=6378245,00

e2=0,006693421623

(e')2=0,006738525415

1. Obliczam B:

ΔB = B2 - B1 = 0,20215233

ΔL = L2 - L1 = 0,0006842

B = = 53,60792784

2. Obliczam C, S, D:

C = = 5,01973E-11

S = = 9,24031E-11

D = = 1,24484E-05

3. Obliczam u i v':

u = = 22499,4672

v' = = 45,28825275

ΔA = ΔL * sinB * [1 + C*(6) + D*(7)] = 0,000550765

4. Obliczam S, Azymut:

S1-2 = = 22499,51278

A = arctg = 0,115328164

A1-2 = A - = 0,115052781

A2-1 = A - ± 180° = 180,1156035

1. Obliczam B:

ΔB = B3 - B2 = 0,00125983

ΔL = L3 - L2 = 0,25135422

B = = 53,70963392

2. Obliczam C, S, D:

C = = 6,74203E-06

S = = 1,25034E-05

D = = 4,8348E-10

3. Obliczam u i v':

u = = 140,2206345

v' = = 16597,50507

ΔA = ΔL * sinB * [1 + C*(6) + D*(7)] = 0,202598607

4. Obliczam S, Azymut:

S2-3 = = 16598,09737

A = arctg = 89,51595981

A2-3 = A - = 89,41466051

A3-2 = A - ± 180° = 269,6172591

1. Obliczam B:

ΔB = B4 - B3 = -0,20377819

ΔL = L4 - L3 = -0,00317294

B = = 53,60837474

2. Obliczam C, S, D:

C = = 1,07952E-09

S = = 1,98723E-09

D = = 1,26494E-05

3. Obliczam u i v':

u = = -22680,42642

v' = = -210,0195743

ΔA = ΔL * sinB * [1 + C*(6) + D*(7)] = -0,002554159

4. Obliczam S, Azymut:

S3-4 = = 22681,39878

A = arctg = 0,530540788

A3-4 = A - = 0,531817867

A4-3 = A - ± 180° = 180,5292637

1. Obliczam B:

ΔB = B4 - B1 = -0,00036603

ΔL = L4 - L1 = 0,24886548

B = = 53,50666866

2. Obliczam C, S, D:

C = = 6,67302E-06

S = = 1,21932E-05

D = = 4,0812E-11

3. Obliczam u i v':

u = = -40,73820271

v' = = 16512,1523

ΔA = ΔL * sinB * [1 + C*(6) + D*(7)] = 0,200069563

4. Obliczam S, Azymut:

S1-4 = = 16512,20255

A = arctg = 270,1413578

A1-4 = A - = 270,0413231

A4-1 = A - ± 180° = 90,24139263

Punkty

S

Azymuty

1,2

22499,513

A1-2 = 0° 06' 54'',19 ;

A2-1 = 180° 06' 56'',17

2,3

16598,097

A2-3 = 89° 24' 52'',78

A3-2 = 269° 37' 02'',13

3,4

22681,399

A3-4 = 0° 31' 54'',54

A4-3 = 180° 31' 45'',35

1,4

16512,202

A1-4 = 270° 02' 28'',76

A4-1 = 90° 14' 29'',01

ZESTAWIENIE WYNIKÓW: