UNIWERSYTET ZIELONOGÓRSKI
WYDZIAŁ INŻYNIERII LĄDOWEJ I ŚRODOWISKA
INSTYTUT BUDOWNICTWA
Ć
WICZENIE PROJEKTOWE nr 2 Z MECHANIKI BUDOWLI
Wykonał Piotr Kramski
Rok akademicki 2006 / 2007
Imię .................................................................... Grupa ................................................................
Nazwisko ........................................................... Nr indeksu .........................................................
PROJEKT NR 2 Z MECHANIKI BUDOWLI I
OBLICZANIE PRZEMIESZCZEŃ – ZASADA PRAC WIRTUALNYCH
Korzystając z zasady prac wirtualnych obliczyć zadane przemieszczenia. W zadaniach (oprócz
nr3) zaprojektować pręty układu na maksymalny moment gnący lub siłę normalną (kratownica,
CE w zadaniu nr4) przyjmując R=100MPa. W zadaniu nr2 osobno zaprojektować odcinek BC.
W zadaniu nr3 przyjąć dwuteownik na podstawie ostatniej cyfry numeru indeksu (0=I80,
1=I100 itd.)
Zadanie 1
pionowe B – wpływ M
wzajemny obrót prętów w E – wpływ M
pionowe G – wpływ M, T (porównać wpływ M i T)
a
b
c
a
b
P
M
q
A
C
D
E
F
G
a
B
Zadanie 2
poziome A – wpływ M, T, N (porównać wpływ M, T i N)
obrót B – wpływ M
wzajemne zbliżenie A i D – wpływ M
obrót cięciwy AD – wpływ M
q
P
M
a
b
c
A
C
B
D
E
c
Zadanie 3
pionowe C, obrót D – wpływ temperatury i osiadania podpór
poziome D – wpływ osiadania podpór
obrót B – wpływ temperatury
t
1
A
B
C
D
E
2Δ
Δ
Δ
α
t
2
a
b
c
Zadanie 4
pionowe i obrót D – wpływ M, N
23 A
Piotr
Kramski
47616
For Evaluation Only.
Copyright (c) by Foxit Software Company, 2004
Edited by Foxit PDF Editor
a
b
c
a
q
P
A
B
C
D
E
M
Zadanie 5
pionowe C, poziome A, kąt obrotu EC, wzajemny kąt obrotu EC i GC – wpływ N
a
b
b
c
P
P
P
P
A
B
C
D
E
F
G
Zadanie 6
pionowe i poziome D, obrót C – wpływ M
Dane do wszystkich zadań:
a=............... [m] (liczba liter w imieniu/2)
b=............... [m] (liczba liter w nazwisku/2)
c=............... [m] (średnia cyfr numeru indeksu)
P=............... [kN] (liczba liter w imieniu)
M=............... [kNm] (przedostatnia cyfra numeru indeksu, jeśli 0 to przyjąć 10)
q=............... [kN/m] (ostatnia cyfra numeru indeksu, jeśli 0 to przyjąć 10)
t
1
=............... [°C] (-liczba liter w imieniu
∗
2)
t
2
=............... [°C] (+liczba liter w nazwisku
∗
2)
t
m
=............... [°C] (+liczba liter w imieniu/2)
α=............... [rad] (średnia cyfr numeru indeksu/100)
Δ=............... [m] (liczba liter w imieniu/200)
Termin oddania: ..............................
P
a
b
a
a
A
B
C
D
2,5
3,5
4,8
5
1
6
-10
+14
+2,5
0,048
0,025
04.02.2007
For Evaluation Only.
Copyright (c) by Foxit Software Company, 2004
Edited by Foxit PDF Editor
ZADANIE 1
a)
przemieszczenie pionowe punktu B – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
B
1
01
,
0
10
5740
10
205
67
,
119
67
,
119
5
,
2
3
1
31
,
23
5
,
2
2
1
5
,
2
3
2
13
,
34
5
,
2
2
1
1
1
8
6
−
=
−
=
=
⋅
⋅
⋅
−
=
−
=
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
=
−
δ
b)
obrót w punkcie E – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
(
)
cm
m
EI
EI
E
4
04
,
0
10
5740
10
205
38
,
475
38
,
475
1
5
,
0
5
,
2
8
5
,
2
6
3
2
1
3
1
5
,
0
5
,
2
75
,
37
1
5
,
0
92
,
2
5
,
0
8
,
4
8
8
,
4
6
3
2
92
,
2
3
2
92
,
2
5
,
0
3
1
5
,
0
8
,
4
64
,
32
93
,
2
3
2
5
,
0
64
,
32
5
,
3
17
,
4
5
,
0
3
2
5
,
2
5
,
0
31
,
23
17
,
4
5
,
0
3
2
17
,
4
3
1
5
,
0
31
,
23
5
,
2
17
,
4
3
2
17
,
4
5
,
0
3
1
5
,
0
5
,
2
13
,
34
1
1
8
6
2
2
−
=
−
=
⋅
⋅
⋅
−
=
−
=
=
⋅
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
−
−
⋅
+
⋅
⋅
⋅
⋅
⋅
+
⋅
+
⋅
⋅
⋅
⋅
⋅
−
−
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
⋅
−
−
⋅
⋅
+
⋅
⋅
⋅
⋅
−
⋅
+
⋅
⋅
⋅
⋅
⋅
−
=
=
−
δ
c)
przemieszczenie pionowe punktu G – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
G
7
,
5
057
,
0
10
5740
10
205
38
,
675
38
,
675
2
5
,
3
5
,
3
8
5
,
3
6
3
2
5
,
3
3
2
5
,
0
575
,
36
5
,
3
5
,
3
5
,
0
5
,
2
8
5
,
2
6
3
2
5
,
3
3
2
5
,
0
75
,
37
5
,
2
75
2
1
8
,
4
8
8
,
4
6
3
2
75
,
6
3
2
5
,
0
64
,
32
8
,
4
75
,
6
3
2
5
,
0
64
,
32
5
,
3
82
,
4
3
2
5
,
0
31
,
23
5
,
2
64
,
9
3
1
5
,
0
31
,
23
5
,
2
64
,
9
3
2
5
,
0
13
,
34
5
,
2
1
1
8
6
2
2
2
−
=
−
=
⋅
⋅
⋅
−
=
−
=
=
⋅
⋅
⋅
⋅
−
−
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
+
+
⋅
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
−
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
=
−
δ
d)
przemieszczenie pionowe punktu G – wpływ T
ds
GA
T
T
P
∑
∑∫
∂
=
l
δ
(
) (
) (
) (
)
(
) (
) (
)
cm
GA
GA
G
046
,
0
410
,
53
10
80
33
,
2
872
,
83
872
,
83
1
5
,
0
5
,
3
21
4
,
1
5
,
0
5
,
2
6
,
7
4
,
1
5
,
0
5
,
2
6
,
22
4
,
1
5
,
0
8
,
4
6
,
7
4
,
1
5
,
0
8
,
4
2
,
21
92
,
1
3
,
9
6
92
,
1
5
,
2
3
,
4
1
6
6
−
=
⋅
⋅
⋅
−
=
∂
−
=
=
⋅
⋅
⋅
+
⋅
⋅
⋅
+
⋅
⋅
⋅
+
+
⋅
⋅
⋅
+
⋅
⋅
⋅
−
⋅
⋅
−
⋅
⋅
−
∂
=
−
l
l
δ
3
5
,
377
3775
,
0
100
75
,
37
max
max
cm
W
W
W
W
R
M
R
W
M
=
≥
≤
≤
≤
Przyjmuję dwuteownik 260
h=260mm
s=113mm
g=9,3mm
t=14,1mm
Ix=5740cm
4
A=53,4cm
2
,
G=80GPa,
E=205GPa
(
)
33
,
2
41
,
1
26
93
,
0
4
,
53
)
(
=
−
⋅
=
−
⋅
=
=
∂
t
h
g
A
Asr
A
l
ZADANIE 2
Projektuję pręt układu na maksymalny moment gnący
MPa
R
W
R
M
R
W
M
100
max
max
=
≤
≤
a) dla pręta A – B (EI
1
)
3
3
214
5
,
177
1000
100
1000000
75
,
17
75
,
17
max
cm
W
W
cm
kNm
M
=
≤
=
⋅
⋅
=
Przyjmuję dwuteownik 200
h=200mm
s=90mm
g=7,5mm
t=11,3mm
A=33,5cm
2
I=2140cm
4
G=80*10
6
Pa
E=205*10
6
Pa
(
)
367
,
2
13
,
1
20
75
,
0
5
,
33
=
−
⋅
=
=
∂
Asr
A
l
b) dla pręta B – C (EI
2
)
3
3
2380
7
,
2066
1000
100
1000000
67
,
206
67
,
206
max
cm
W
W
cm
kNm
M
=
≤
=
⋅
⋅
=
Przyjmuję dwuteownik 475
h=475mm
s=178mm
g=17,1mm
t=25,6mm
A=163cm
2
I=56480cm
4
G=80*10
6
Pa
E=205*10
6
Pa
(
)
121
,
2
56
,
2
5
,
47
71
,
1
163
=
−
⋅
=
=
∂
Asr
A
l
c) dla pręta C – D (EI
3
)
3
3
782
2
,
691
1000
100
1000000
12
,
69
12
,
69
max
cm
W
W
cm
kNm
M
=
≤
=
⋅
⋅
=
Przyjmuję dwuteownik 320
h=320mm
s=131mm
g=11,5mm
t=17,3mm
A=77,8cm
2
I=12510cm
4
G=80*10
6
Pa
E=205*10
6
Pa
(
)
234
,
2
73
,
1
32
15
,
1
8
,
77
=
−
⋅
=
=
∂
Asr
A
l
d) dla pręta B – E (EI
4
)
3
3
2040
2
,
1889
1000
100
1000000
92
,
188
92
,
188
max
cm
W
W
cm
kNm
M
=
≤
=
⋅
⋅
=
Przyjmuję dwuteownik 450
h=450mm
s=170mm
g=16,2mm
t=24,3mm
A=147cm
2
I=45850cm
4
G=80*10
6
Pa
E=205*10
6
Pa
(
)
131
,
2
43
,
2
45
62
,
1
147
=
−
⋅
=
=
∂
Asr
A
l
a)
przemieszczenie pionowe punktu A – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
EI
EI
A
9
,
1
019
,
0
10
45850
10
205
84
,
1582
10
2140
10
205
03
,
158
84
,
1582
03
,
158
8
,
4
3
1
8
,
4
92
,
164
5
,
0
8
,
4
3
2
8
,
4
92
,
188
5
,
0
1
8
,
4
3
1
412
,
5
1
5
,
0
8
,
4
3
2
412
,
5
75
,
17
5
,
0
1
1
8
6
8
6
4
1
4
1
=
=
⋅
⋅
⋅
−
⋅
⋅
⋅
=
=
−
=
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
⋅
+
+
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
=
−
−
δ
b)
przemieszczenie pionowe punktu A – wpływ T
ds
GA
T
T
P
∑
∑∫
∂
=
l
δ
[
]
[
]
cm
m
GA
GA
GA
GA
A
1
01
,
0
10
147
10
80
24
131
,
2
10
5
,
33
10
80
617
,
16
361
,
2
24
617
,
16
1
8
,
4
5
89
,
0
412
,
5
5
,
0
9
,
6
1
6
6
6
6
4
4
1
1
4
4
1
1
=
=
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
=
=
⋅
∂
−
⋅
∂
=
⋅
⋅
⋅
∂
−
⋅
⋅
⋅
⋅
∂
=
−
−
l
l
l
l
δ
c)
przemieszczenie pionowe punktu A – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
(
)
[
]
cm
m
EA
A
241
,
0
00241
,
0
10
5
,
33
10
205
56
,
16
46
,
0
412
,
5
5
,
0
3
,
13
1
1
6
6
1
=
=
⋅
⋅
⋅
−
=
⋅
⋅
⋅
−
⋅
=
−
δ
d)
obrót w punkcie B – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
[
]
cm
m
EI
B
9
,
0
009
,
0
10
45850
10
205
216
,
849
1
8
,
4
92
,
164
5
,
0
1
8
,
4
92
,
188
5
,
0
1
1
8
6
4
=
=
⋅
⋅
⋅
=
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
=
−
δ
e) wzajemne zbliżanie się A i D – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
EI
AD
19
,
4
0419
,
0
10
12510
10
205
175
,
140
10
56480
10
205
274
,
1291
10
2140
10
205
279
,
111
69
,
1
5
,
0
8
,
4
8
8
,
4
6
3
2
69
,
1
3
2
8
,
4
12
,
69
5
,
0
1
38
,
3
4
3
5
,
3
8
5
,
3
6
3
2
69
,
1
3
2
38
,
3
3
1
5
,
3
12
,
69
5
,
0
38
,
3
3
2
69
,
1
3
1
5
,
3
67
,
206
5
,
0
1
38
,
3
3
1
412
,
5
5
,
0
1
38
,
3
3
2
412
,
5
5
,
0
75
,
17
1
1
8
6
8
6
8
6
2
3
2
2
1
=
=
⋅
⋅
⋅
+
⋅
⋅
⋅
+
+
⋅
⋅
⋅
=
⋅
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
⋅
+
+
⋅
⋅
⋅
⋅
⋅
−
−
⋅
+
⋅
⋅
⋅
⋅
+
⋅
+
⋅
⋅
⋅
⋅
⋅
+
+
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
=
−
−
−
δ
f)
obrót cięciwy AD – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
EI
EI
AD
5
,
17
175
,
0
107
,
0
0123
,
0
0239
,
0
0317
,
0
10
45850
10
205
733
,
10037
10
12510
10
205
357
,
314
10
56480
10
205
94
,
2773
10
2140
10
205
26
,
139
82
,
11
8
,
4
5
,
0
92
,
164
82
,
11
8
,
4
5
,
0
92
,
188
1
58
,
7
4
1
8
,
4
8
8
,
4
6
3
2
79
,
3
3
2
8
,
4
12
,
69
5
,
0
1
58
,
7
3
1
79
,
3
3
2
5
,
3
12
,
69
5
,
0
58
,
7
3
2
79
,
3
3
1
5
,
3
67
,
206
5
,
0
58
,
7
4
3
5
,
3
8
5
,
3
6
3
2
1
23
,
4
3
2
412
,
5
5
,
0
75
,
17
23
,
4
3
1
412
,
5
5
,
0
1
1
1
8
6
8
6
8
6
8
6
4
2
3
2
2
1
=
=
+
+
+
=
=
⋅
⋅
⋅
+
⋅
⋅
⋅
+
⋅
⋅
⋅
+
⋅
⋅
⋅
−
=
=
⋅
⋅
⋅
+
+
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
⋅
+
+
⋅
+
⋅
⋅
⋅
⋅
+
+
⋅
+
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
−
⋅
+
+
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
−
⋅
=
−
−
−
−
δ
ZADANIE 3
Przyjmuję dwuteownik 200
367
,
2
3
,
0
10
205
10
85
,
78
85
,
78
)
1
(
2
2140
5
,
33
13
,
1
75
,
0
9
20
6
6
4
2
=
=
∂
=
⋅
=
⋅
=
=
+
⋅
=
=
=
=
=
=
=
sr
A
A
Pa
E
Pa
GPa
E
G
cm
I
cm
A
cm
t
cm
g
cm
s
cm
h
l
υ
υ
C
t
t
t
t
m
°
=
⋅
−
=
5
2
2
1
0
α
2∆
∆
∆
∆
a)
przemieszczenie pionowe punktu C – wpływ temperatury i osiadania podpór
∑∫
∑
∑∫
∑
⋅
+
∆
⋅
=
∆
+
ds
t
N
ds
h
t
M
M
R
P
t
t
0
α
α
δ
[
]
(
)
(
)
453
,
2
048
,
0
24
363
8
,
4
048
,
0
025
,
0
1
24
363
025
,
0
1
5
8
,
4
1
24
5
,
2
5
,
2
2
1
24
8
,
4
5
,
2
1
025
,
0
1
−
=
⋅
+
−
⋅
=
−
+
−
⋅
=
−
⋅
⋅
+
⋅
⋅
⋅
−
⋅
⋅
−
=
⋅
−
D
D
t
t
D
t
t
D
h
h
δ
δ
α
α
δ
α
α
δ
b)
obrót punktu D - wpływ temperatury i osiadania podpór
∑∫
∑
∑∫
∑
⋅
+
∆
⋅
=
∆
+
ds
t
N
ds
h
t
M
M
R
P
t
t
0
α
α
δ
[
]
429
,
1
09
,
145
8
,
4
048
,
0
0217
,
0
1
09
,
145
0217
,
0
1
2
8
,
4
29
,
0
2
8
,
4
29
,
0
24
71
,
0
8
,
4
24
71
,
0
5
,
2
2
1
24
1
5
,
3
2
1
29
,
0
05
,
0
025
,
0
29
,
0
1
=
⋅
=
+
⋅
=
+
⋅
⋅
−
⋅
⋅
+
+
⋅
⋅
+
⋅
⋅
⋅
+
⋅
⋅
⋅
=
⋅
+
⋅
+
D
D
t
D
t
t
D
h
h
δ
δ
α
δ
α
α
δ
c)
przemieszczenie poziome D – osiadanie podpór
∑∫
∑
∑
⋅
=
∆
+
ds
t
N
R
P
t
0
α
δ
[
]
( )
( )
576
,
0
12
048
,
0
1
12
1
2
6
1
1
−
=
−
⋅
=
−
⋅
=
⋅
⋅
−
=
D
D
t
D
t
D
δ
δ
α
δ
α
δ
d)
obrót w punkcie B – wpływ temperatury
ds
h
t
M
M
R
P
t
∑
∑∫
∑
∆
⋅
=
∆
+
α
δ
[
]
(
)
(
)
177
,
1
2
,
115
8
,
4
048
,
0
025
,
0
1
2
,
115
025
,
0
1
24
8
,
4
1
3
1
025
,
0
05
,
0
3
1
1
−
=
−
⋅
=
+
−
⋅
=
+
⋅
⋅
−
=
−
⋅
−
⋅
+
B
B
t
B
t
B
h
h
δ
δ
α
δ
α
δ
ZADANIE 4
Projektuję pręty układu na maksymalny moment gnący i siłę normalną
A
R
N
R
A
N
W
R
M
R
W
M
MPa
R
≤
≤
≤
≤
=
max
max
max
max
100
1. Pręty A- B, B – C, C – D na Momot gnący
3
278
240
1000
100
1000000
24
cm
W
W
=
≤
=
⋅
⋅
Przyjmuję dwuteownik 220
35
,
2
10
205
10
80
3060
6
,
39
22
,
1
81
,
0
8
,
9
22
6
6
4
2
=
∂
⋅
=
⋅
=
=
=
=
=
=
=
l
Pa
E
Pa
G
cm
I
cm
A
cm
t
cm
g
cm
s
cm
h
2. Pręt C – E na maksymalną siłę normalną
2
3
4
58
,
7
26
,
2
10
100
10
6
,
22
cm
A
A
=
≤
=
⋅
⋅
Przyjmuję dwuteownik 80
623
,
2
10
205
10
80
8
,
77
58
,
7
59
,
0
39
,
0
2
,
4
8
6
6
4
2
=
∂
⋅
=
⋅
=
=
=
=
=
=
=
l
Pa
E
Pa
G
cm
I
cm
A
cm
t
cm
g
cm
s
cm
h
a)
przemieszczenie pionowe punktu D – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
D
99
,
4
0499
,
0
10
3060
10
205
4
,
313
8
,
4
3
1
5
,
3
5
,
0
9
,
1
8
,
4
5
,
0
5
,
3
8
5
,
3
6
3
2
8
,
4
3
2
5
,
3
24
5
,
0
8
,
4
3
2
8
,
4
24
5
,
0
1
1
8
6
2
=
=
⋅
⋅
⋅
=
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
⋅
=
−
δ
b)
przemieszczenie pionowe punktu D – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
D
6
,
8
086
,
0
10
58
,
7
10
205
9
,
133
9
,
133
37
,
2
5
,
2
6
,
22
1
1
6
6
=
=
⋅
⋅
⋅
=
=
⋅
⋅
=
−
δ
c)
obrót w punkcie D – wpływ M
ds
EI
M
M
P
∑
∑∫
=
δ
cm
m
EI
EI
D
17
,
1
0117
,
0
10
3060
10
205
77
,
73
77
,
73
1
3
1
5
,
3
5
,
0
9
,
1
1
5
,
0
5
,
3
8
5
,
3
6
3
2
1
3
2
5
,
3
24
5
,
0
1
8
,
4
24
5
,
0
1
1
8
6
2
=
=
⋅
⋅
⋅
=
=
=
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
⋅
−
⋅
⋅
⋅
⋅
+
⋅
⋅
⋅
=
−
δ
d)
obrót w punkcie D – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
D
05
,
1
0105
,
0
10
58
,
7
10
205
38
,
16
38
,
16
29
,
0
5
,
2
6
,
22
1
1
6
6
=
=
⋅
⋅
⋅
=
=
⋅
⋅
=
−
δ
ZADANIE 5
Projektuję pręt układu na maksymalną siłę normalną
2
3
4
58
,
7
734
,
0
10
100
10
34
,
7
cm
A
A
A
R
N
R
A
N
=
≤
=
⋅
⋅
≤
≤
Przyjmuję dwuteownik 80
623
,
2
10
205
10
80
8
,
77
58
,
7
59
,
0
39
,
0
2
,
4
8
6
6
4
2
=
∂
⋅
=
⋅
=
=
=
=
=
=
=
l
Pa
E
Pa
G
cm
I
cm
A
cm
t
cm
g
cm
s
cm
h
a)
przemieszczenie pionowe punktu C – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
C
53
,
2
0253
,
0
10
58
,
7
10
205
277
,
39
277
,
39
48
,
0
8
,
4
34
,
7
57
,
0
94
,
5
72
,
2
57
,
0
94
,
5
67
,
2
35
,
0
7
68
,
1
1
1
6
6
=
=
⋅
⋅
⋅
=
=
=
⋅
⋅
+
⋅
⋅
+
⋅
⋅
+
⋅
⋅
⋅
=
−
δ
b)
przemieszczenie poziome punktu A – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
A
08
,
3
0308
,
0
10
58
,
7
10
205
97
,
47
97
,
47
1
5
,
3
06
,
5
1
5
,
3
06
,
5
1
5
,
2
06
,
5
1
1
6
6
=
=
⋅
⋅
⋅
−
=
−
=
⋅
⋅
−
⋅
⋅
−
⋅
⋅
−
=
−
δ
c)
kąt obrotu EC – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
EC
022
,
0
10
2
,
2
10
58
,
7
10
205
34
,
0
34
,
0
138
,
0
8
,
4
34
,
7
167
,
0
93
,
5
72
,
2
05
,
0
93
,
5
67
,
2
1
,
0
7
68
,
1
137
,
0
8
,
4
98
,
7
1
1
4
6
6
=
⋅
=
⋅
⋅
⋅
=
=
=
⋅
⋅
+
⋅
⋅
+
⋅
⋅
−
⋅
⋅
−
⋅
⋅
−
=
−
−
δ
d)
wzajemny kąt obrotu EC i GC – wpływ N
ds
EA
N
N
P
∑
∑∫
=
δ
[
]
cm
m
EA
EA
GC
EC
343
,
0
00343
,
0
10
58
,
7
10
205
327
,
5
327
,
5
136
,
0
7
68
,
1
1
,
0
8
,
4
34
,
7
1
,
0
8
,
4
09
,
7
1
1
6
6
=
=
=
⋅
⋅
⋅
=
=
⋅
⋅
−
⋅
⋅
+
⋅
⋅
=
−
−
δ
ZADANIE 6
Projektuję pręty układu na maksymalny moment gnący
3
278
240
1000
100
1000000
25
cm
W
W
=
≤
=
⋅
⋅
Przyjmuję dwuteownik 220
35
,
2
10
205
10
80
3060
6
,
39
22
,
1
81
,
0
8
,
9
22
6
6
4
2
=
∂
⋅
=
⋅
=
=
=
=
=
=
=
l
Pa
E
Pa
G
cm
I
cm
A
cm
t
cm
g
cm
s
cm
h
a)
przemieszczenie pionowe punktu D – wpływ M
(
)
(
)
x
a
M
x
a
P
Mp
−
⋅
−
=
−
⋅
−
=
1
ds
EI
Mp
M
ds
EI
Mp
M
ds
EI
M
M
P
D
B
B
A
∫
∫
∑
∑∫
⋅
+
⋅
=
=
δ
[
]
cm
m
EI
EI
ds
EI
Mp
M
B
A
97
,
6
0697
,
0
10
3060
10
205
5
,
437
5
,
437
5
5
,
3
25
1
8
6
=
=
⋅
⋅
⋅
=
=
⋅
⋅
=
⋅
−
∫
(
) ( )
( ) (
)
(
)
cm
cm
m
d
d
d
EI
ds
x
x
EI
ds
x
x
EI
ds
x
x
EI
ds
EI
x
a
x
a
P
ds
EI
Mp
M
V
D
D
B
D
B
D
B
D
B
92
,
8
97
,
6
95
,
1
95
,
1
0195
,
0
10
3060
10
205
125
,
78
5
,
0
cos
125
,
78
cos
25
,
156
125
,
78
1
5
25
25
,
31
1
)
5
,
2
(
)
5
5
,
12
(
1
5
,
2
1
)
5
,
2
(
)
5
(
1
)
(
1
8
6
0
0
0
2
2
=
+
=
=
=
=
⋅
⋅
⋅
⋅
⋅
=
⋅
+
⋅
−
⋅
=
=
+
−
⋅
=
+
−
⋅
+
−
⋅
=
=
−
⋅
−
⋅
−
⋅
−
⋅
=
−
⋅
−
⋅
−
⋅
−
=
⋅
−
∫
∫
∫
∫
∫
∫
∫
δ
π
ϕ
ϕ
ϕ
ϕ
ϕ
π
π
π
b)
przemieszczenie poziome punktu D – wpływ M
y
M
x
x
a
P
Mp
a
y
a
x
−
=
−
⋅
−
=
−
⋅
−
=
⋅
=
⋅
=
)
5
,
2
(
5
)
(
sin
cos
ϕ
ϕ
∫
∫
∑∫
⋅
+
⋅
=
⋅
=
D
B
B
A
H
D
ds
EI
Mp
M
ds
EI
Mp
M
ds
EI
Mp
M
δ
[
]
(
)
cm
cm
m
EI
d
EI
d
EI
ds
y
xy
EI
ds
y
x
EI
ds
EI
Mp
M
cm
m
EI
ds
EI
Mp
M
H
D
D
B
D
B
D
B
B
A
93
,
4
49
,
2
44
,
2
49
,
2
0249
,
0
10
3060
10
205
25
,
156
2
125
,
78
)
sin
sin
cos
(
125
,
78
5
,
2
sin
5
,
2
5
,
12
sin
5
,
2
cos
5
,
2
5
1
)
5
,
12
5
(
1
)
(
)
5
,
12
5
(
1
44
,
2
0244
,
0
10
3060
10
205
125
,
153
5
,
3
5
,
0
5
,
3
25
1
0
8
6
8
6
=
+
=
=
=
⋅
⋅
⋅
=
⋅
=
+
⋅
−
⋅
=
=
⋅
⋅
⋅
+
⋅
⋅
⋅
⋅
−
⋅
=
=
+
−
⋅
=
−
⋅
−
⋅
=
⋅
=
=
⋅
⋅
⋅
=
⋅
⋅
⋅
⋅
=
⋅
∫
∫
∫
∫
∫
−
−
δ
ϕ
ϕ
ϕ
ϕ
ϕ
ϕ
ϕ
ϕ
π
c)
obrót punktu C – wpływ M
1
5
,
12
5
)
(
=
−
=
−
⋅
−
=
M
x
Mp
x
a
P
M
(
)
cm
m
EI
ds
EI
Mp
M
ds
EI
Mp
M
ds
EI
Mp
M
ds
EI
Mp
M
c
B
A
C
B
B
A
99
,
0
00996
,
0
10
3060
10
205
5
,
62
1
5
,
3
25
1
8
6
=
=
⋅
⋅
⋅
=
⋅
⋅
⋅
=
⋅
=
⋅
+
⋅
=
⋅
=
−
∫
∫
∫
∑∫
δ
(
)
cm
c
cm
m
EI
d
EI
d
EI
ds
x
EI
ds
EI
Mp
M
C
B
C
B
29
,
0
28
,
1
99
,
0
28
,
1
0128
,
0
10
3060
10
205
57
,
2
25
,
31
2
1
25
,
31
)
1
(cos
25
,
31
5
,
2
)
25
,
31
cos
25
,
31
(
1
1
)
5
,
12
5
(
1
2
8
6
2
−
=
−
=
−
=
−
=
⋅
⋅
⋅
−
⋅
=
−
−
⋅
=
−
⋅
=
=
⋅
−
⋅
⋅
=
⋅
−
⋅
=
⋅
∫
∫
∫
∫
−
ϕ
π
ϕ
ϕ
ϕ
ϕ
π
π
π
π