Reakcje podporowe:

- DACH ( A ):

$$\mathbf{R}_{\mathbf{2}\mathbf{,}\mathbf{k}}\mathbf{=}\mathbf{9}\mathbf{,685}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{2}\mathbf{,}\mathbf{d}}\mathbf{=}\mathbf{13}\mathbf{,291}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{1}\mathbf{,}\mathbf{k}}\mathbf{= 10,880}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{1}\mathbf{,}\mathbf{d}}\mathbf{=}\mathbf{15,094}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

- STROP ( B ):

$$\mathbf{R}_{\mathbf{4}\mathbf{,}\mathbf{k}}\mathbf{=}\mathbf{9}\mathbf{,721}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{4}\mathbf{,}\mathbf{d}}\mathbf{= 13,686}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{3}\mathbf{,}\mathbf{k}}\mathbf{=}\mathbf{9,721}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{3}\mathbf{,}\mathbf{d}}\mathbf{=}\mathbf{13,686}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

- SCHODY ( G ):

$$\mathbf{R}_{\mathbf{5}\mathbf{,}\mathbf{k}}\mathbf{=}\mathbf{12}\mathbf{,055}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{5}\mathbf{,}\mathbf{d}}\mathbf{= 16,749}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{6}\mathbf{,}\mathbf{k}}\mathbf{=}\mathbf{10}\mathbf{,829}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

$$\mathbf{R}_{\mathbf{5}\mathbf{,}\mathbf{d}}\mathbf{= 1}\mathbf{5}\mathbf{,}\mathbf{095}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

ZESTAWIENIE OBCIĄŻEŃ:

OBCIĄŻENIE PRZYPADAJĄCE NA ŁAWĘ H₁:

H_1, k = R_1, k + q_w1, k + R_3, k + q_D, k * (3,85−0,24)m + q_F, k * 1, 0m + q_H1, k

$$H_{1,k} = 10,880\frac{\text{kN}}{m} + 1,501\frac{\text{kN}}{m} + 9,721\frac{\text{kN}}{m} + 3,789\frac{\text{kN}}{m^{2}}*\left( 3,61 \right)m +$$

$$+ 6,440\frac{\text{kN}}{m^{2}}*1,0m + 5,25\frac{\text{kN}}{m}$$

$$\mathbf{H}_{\mathbf{1},\mathbf{k}} = \mathbf{47,470}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

H_1, d = R_1, d + q_w1, d + R_3, d + q_D, d * (3,85−0,24)m + q_F, d * 1, 0m + q_H1, d

$$H_{1,d} = 15,094\frac{\text{kN}}{m} + 2,027\frac{\text{kN}}{m} + 13,686\frac{\text{kN}}{m} + 5,116\frac{\text{kN}}{m^{2}}*\left( 3,61m \right) + 8,696\frac{\text{kN}}{m^{2}}*1,0m + 7,128\frac{\text{kN}}{m}$$

$$\mathbf{H}_{\mathbf{1},\mathbf{d}} = \mathbf{65,100}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

OBCIĄŻENIE PRZYPADAJĄCE NA ŁAWĘ H₄:

H_4, k = q_w1, k + q_D, k * (5,5−0,24)m + q_F, k * 1, 0m + q_H4, k

$$H_{4,k} = 1,501\frac{\text{kN}}{m} + 3,789\frac{\text{kN}}{m^{2}}*\left( 5,26 \right)m + 6,440\frac{\text{kN}}{m^{2}}*1,0m + 5,280\frac{\text{kN}}{m}$$

$$\mathbf{H}_{\mathbf{4},\mathbf{k}} = \mathbf{33},\mathbf{151}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$

H_4, d = q_w1, d + q_D, d * (5,5−0,24)m + q_F, d * 1, 0m + q_H4, d

$$H_{4,d} = 2,027\frac{\text{kN}}{m} + 5,116\frac{\text{kN}}{m^{2}}*\left( 5,26 \right)m + 8,696\frac{\text{kN}}{m^{2}}*1,0m + 7,128\frac{\text{kN}}{m}$$

$$\mathbf{H}_{\mathbf{4},\mathbf{d}} = \mathbf{44},\mathbf{761}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$