11 stycznia 2006 Albercik
SYABILITY 2
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BASICS OF GAMAGE STABILITY THEORY
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1. Pyt. Which of following statements are true, with respect to change of stability parameters
for a damaged ship?
M meves,B moves and Gm
2. Pyt. What statements is true about the matecentric radiaus?
B Odp. The matecentric radiaus is the distance between B and matecentre, depending on the
displacement and the moment of inertia of the waterplane area.
DAMAGE STABILITY THEORY
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1. Pyt. Cick and drag the different terms to their corresponging boxes.
Odp. Double bottom domage, amid ship.Symetrical two compartment damage in the aft ship.
Symmetrcal three compartment damage in the fore ship.Two compartment,unsymmetri
cal damage the aft ship.
2. Pyt. Whivh statements are true concerning the added weight method:
Odp. A - since the method is similar to an ordinary load calculalation and D - since the free
surface has effect on the stability both at unsymmetrical and symmetrical damage.
3. Pyt. In the added weight method,the free communication effect in damaged condition:
C Odp. Reduces the GM and decreases the dynamic stability by sinus correction of the GZ
curve.
4. Pyt. Which statements are true concerning the Loss of Buoyancy method:
B Odp. The damaged compartment is considered nonexisting.
DAMAGE STABILITY REGULATIONS
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1. Pyt. What is the minimum required righting lever for a damaged passenger ship at
intermediate state of flooding?
B Odp. 0,05 meters.
2. Pyt. What is the minimum required righting lever for a damaged passenger ship at final
state of flooding.?
B Odp. 0,10 meters.
3. Pyt. What is the minimum required residuary dynamic stability for a damaged passenger
ship at equiligrum?
C Odp. 0,015 metre - radians.
4. Pyt. Click and drag the differents terms to their corresponding boxes:
Odp. Weatherting
Subdivision load line
Progressive flooding
Residual stability
Margin line
STABILITY ASSESSMENT TABLE
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1. Pyt. What is the minimum required GM for a ship with following GMmin curve and draught
6,3 meter.
A Odp. 1,7 m.
2. Pyt. What is the maximal permisible draught for the ship to full fill the stability requiremants?
D Odp. Draught 6,0 m gives: Draught 6,5 m gives:
GM = KM - KG =10 65 - 9,80 = 0,85 m GM = KM - KG = 10,66 - 9,80 = 0,86 m
Alloved, because GMmin6,0 = 0,78 m Alloved, because GMmin6,5 = 0,6 m
Draught 7,0 m gives: Draught 7,5 m gives:
GM = KM - KG = 10,78 - 9,80 = 0,98 m GM = KM - KG = 10,85 - 9,80 = 1,05 m
Alloved, because GM min 7,0 = 0,8 m Not alloved, because GMmin 7,5 = 1,5 m
3. Pyt. How many damaged compartments does the following ship survive?
Click on the different wateright compartmeents and analyse the triangles.
B Odp. 2 - compartments.
4. Pyt. Which of the following statement(s) are tru?
Odp. B and C
ASSESSMENTS
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16 pytan - powtorka wszystkich poprzednich !