Kolo Chemia 3

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I mol CH4 * 4 (j.02 I0^JJatonio", n 3 mole CHj -    x x - 7? : • iu . _m0w H

1 mol CG -    22

0.2 mola CO -    \

⁴ •    - aoia = 4.48 dm³

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Cu S - 4 I ' 5 g Cu_:S 5 a Cu;S-----1 u Cu

80 g Cu;$-

-X

80 4

X = -= 6 '■

5g Cu_:S......I u S

80 a Cu;S-----x x ~ 16 a S

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NHaHCO, = CO; + NHi - H;0 m NH₄HC0; - m CO_; + m NH, -m I1_:0 ’ m CO; = V J = 4.48 1.96 - SJSg

m NH-! = I 5. 8 - (8.79 + 3.t>) - 3.4 Ig V NH₃ = m. d = 3.41 /Q.7b - 4.48 dm’’

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I mol H;SO-t 04g O 2mol H;SO.i x Mco=28 g/mol 28 g CO ~ 22.4dm*

10 a CO x

x— 128 a O

x= 8 dm’ CO

Fe:O 7:2 =9 g	FeO
9 g FeO 7Fe	20
72 g FeO x	V ./
x =56 u Fe	V Łś

2 hU)

= ^m;u +

m_H - v • d - 4dm* 0.089g/ dm* = 0.356g

m_a = 2dm'' \A5g/dm* = 2.86g m_H%0 = 2.861? -r 0.356# = 3,216#

lmoINH₃ 6.02 10^:j 0.3 mola    x x =0.3 6.02 10²³

= 18^ i mol

18gH_:0    22.4dm⁵

x    4,48 dm^ł    x= 3.6    H;0

—

Mg: Cl 12:35 =47 gMgCl;

47 g MgCl;    12g Mg i 35gCl;

94g MgCl; x    y

U    - 64 - 32 + 64 - 5 18 = 250

^lv‘CuSOffUp

x =24u Mu \ = ^Ou Cl;

W    W    •    ^

250g    100°o

90g H;0 x x = 36 % H;0