ANTIDERIVATIVES
An antiderivative, (primitive or indefinite integral) of a
function f is a function F whose derivative is equal to f,
i.e., F ′ = f.
Definition
A differentiable function F defined on (a, b), for which:
F '(x) = f (x),
for every x
(a, b)
is called an
antiderivative
of the function f on the interval (a, b).
Remark
If F is some specific antiderivative of a function f on (a, b),
then all the antiderivatives are given by the formula
The graphs of antiderivatives of a given function are vertical
translations of each other; each graph's location depending upon the
value of C.
The constant C is called the arbitrary constant of integration.
G(x) = F(x) + C, where C is a real constant.
Antiderivative of y = 2x,
they fill up the whole plane without
overlapping.
We identify a curve as the one which
passes through the given point, i.e. (0,0)
If the domain of F is a disjoint union of two or more
intervals, then a different constant of integration may be
chosen for each of the intervals. For instance
is the most general antiderivative of
)
,
0
(
)
0
,
(
,
1
)
(
2
x
x
x
f
Definition
The set of all antiderivatives of a function f is called an
indefinite integral of a function f on (a, b) and is denoted by
This the above symbol is read as: "an integral of f of x over dx".
•The function f is called the integrand
•The variable x is called the integration variable
•The expression dx is called the differential of the integration variable.
dx
x
f )
(
Definition
A function, for which the indefinite integral in a given
interval exists, is said to be integrable on this interval
Definition
A function, for which the indefinite integral in a given
interval exists, is said to be integrable on this interval
Integral of f of x over dx
THEOREM
If a function f is continuous on an interval (a, b),
it is also integrable on this interval.
Fact
There are many functions whose antiderivatives, even though
they exist, cannot be expressed in terms of elementary
functions. These functions are called are not
elementary
integrable
e.g.
3
2
1
)
(
,
sin
)
(
,
ln
1
)
(
),
sin(
)
(
,
)
(
2
x
x
f
x
x
x
f
x
x
f
x
x
f
e
x
f
x
C
x
dx
x
n
n
n
1
1
1
C
x
xdx
2
2
1
C
x
x sin
cos
C
x
xdx
cos
sin
C
a
a
dx
a
x
x
ln
/
C
x
dx
x
|
|
ln
1
C
e
dx
e
x
x
C
x
dx
x
arcsin
1
1
2
C
x
dx
x
arccos
1
1
2
C
x
dx
x
arctan
1
1
2
C
x
arcc
dx
x
tan
1
1
2
C
x
dx
1
BASIC ANTIDERIVATIVES
Theorem (on linearity of an indefinite integral)
If functions f and g are integrable on some interval P, then the
functions f + g and A f , where A denotes any real constant, are
also integrable on this interval too, and
"an integral of a sum equals a sum of integrals",
"a constant can be factored out of the integral".
dx
x
g
dx
x
f
dx
x
g
x
f
)
(
)
(
)]
(
)
(
[
dx
x
f
A
x
f
A
)
(
)
(
Theorem (Integration by Parts)
Suppose f (x) and g(x) are two functions that are
continuously differentiable on some open interval, then in
this interval
In other notation
dx
x
g
x
'
f
x
g
x
f
dx
x
g'
x
f
)
(
)
(
)
(
)
(
)
(
)
(
df
g
g
f
dg
f
[f (x) g(x)]’ = f ’(x) g(x) + f (x) g’(x)
f (x) g’(x) = [f (x) g(x)]’ - f’ (x) g(x)
dx
x
f
x
g
dx
x
g
x
f
dx
x
g
x
f
)
(
'
)
(
)]'
(
)
(
[
)
(
'
)
(
dx
x
f
x
g
x
g
x
f
dx
x
g
x
f
)
(
'
)
(
)
(
)
(
)
(
'
)
(
Proof
QED
Examples
g
f
g
f
'
'
according to Gewert, Skoczylas
Theorem (Integration by Substitution - change of
variable)
Suppose the function f is integrable on an interval P, and t(x)
is a continuously differentiable function which is defined on the
interval [a, b] and whose image (also known as range) is
contained in the domain P of f then
dt
t
f
dx
x
t
x
t
f
)
(
)
(
'
))
(
(
C
x
F
dx
x
f
)
(
)
(
dx
x
t
dt
)
(
'
)
(
'
))
(
(
'
))
(
(
)
(
x
t
x
t
F
x
t
F
dx
d
x
f
F
dx
d
Remarks
•The constant of integration C should be written last
,
after finding the antiderivative. As long as on the right hand
side there is at least one indefinite integral, the constant of
integration doesn't have to appear explicitly, since it is hidden
in the symbol of an indefinite integral.
•The correctness of the result, i.e. of the antiderivative
which was found, can always be
verified by
differentating
the antiderivative; as a result we should
get the integrand.
RATIONAL FUNCTIONS
)
(
)
(
)
(
x
Q
x
P
x
f
INTEGRATION OF RATIONAL FUNCTIONS
Definition
A rational function is a quotient of two polynomials, i.e., a function of the form
where P (x) and Q (x) are polynomials of degree n and m.
If the degree of the numerator is less than the degree of the
denominator, the function is called
a proper rational
function.
Theorem
Any proper rational function can be represented as a sum of the
so called partial fractions of the first kind
and partial fractions of the second kind
where A, B, C, a, p, q are real numbers,
p
2
- 4q < 0
, and k is a natural number
-
irreducible
.
k
a
x
A
)
(
k
q
px
x
C
Bx
)
(
2
PRACTICALLY,
If the degree of P(x) is greater than or equal to the degree of
Q(x), then by
long division
we can express the rational function
by
where q(x) is the quotient and r(x) is the remainder whose
degree is less that the degree of Q(x).
Then Q(x) is factored as a product of powers of linear and
quadratic factors. Finally r(x)/ Q(x) is split into a sum of fractions
which consist of ones of type
and
)
(
)
(
)
(
)
(
)
(
x
Q
x
r
x
q
x
Q
x
P
n
n
a
x
A
a
x
A
a
x
A
)
(
)
(
2
2
1
n
n
n
q
px
x
C
x
B
q
px
x
C
x
B
q
px
x
C
x
B
)
(
)
(
2
2
2
2
2
2
1
1
irreducible quadratic factors
Each factor (x - a)
m
in the denominator of the proper
rational function suggests repeated linear factors
m
i
a
x
A
a
x
A
a
x
A
)
(
)
(
2
2
1
Note that the degree of the terms is from 1 to m.
Each factor (x
2
+ px + q)
m
in the denominator of the
proper rational function suggests repeated irreducible
quadratic facors:
m
m
m
q
px
x
C
x
B
q
px
x
C
x
B
q
px
x
C
x
B
)
(
)
(
2
2
2
2
2
2
1
1
Note that the degree of the terms is from 1 to m.
Examples
http://calc101.com/webMathematica/partial-fractions.jsp
To find the coefficients A
i
.
INTEGRATION OF PARTIAL FRACTIONS
Integration of partial fractions of the first kind
For k = 1
For k > 1
C
a
x
A
dx
a
x
A
ln
C
a
x
k
A
C
k
t
A
dt
t
A
dx
dt
a
x
t
dx
a
x
A
k
k
k
k
1
1
)
)(
1
(
1
1
)
(
n
n
b
ax
A
b
ax
A
b
ax
A
)
(
)
(
2
2
1
We express the integral as a sum of two integrals in such a
way that the numerator of the integrand in the first integral is
the derivative of the denominator:
The first integral on the right hand side can be evaluated by substituting
dx
q
px
x
Bp
C
dx
q
px
x
p
x
B
dx
q
px
x
C
Bx
k
k
k
)
(
1
2
)
(
2
2
)
(
2
2
2
t = x
2
+ px + q,
Integration of partial fractions of
the second kind
m
m
m
c
bx
ax
c
x
B
c
bx
ax
c
x
B
c
bx
ax
c
x
B
)
(
)
(
2
2
2
2
2
2
1
1
For k = 1, we complete the square to represent the trinomial in
the canonical form
Substituting
we obtain the elementary integral
For k > 1, the integral is found by use of an appropriate
recurrence formula (which shall be not considered here).
4
2
2
2
p
q
q
p
x
q
px
x
dt
t
2
1
1
4
2
2
p
q
t
p
x