S	Pd	Pd	R	h	V	$$\frac{\mathbf{V}}{\mathbf{V}_{\mathbf{\max}}}$$	A	qV
[10^-3m]	[mm H2O]	[Pa]	[10 ^-3m]	[10 ^-3 m]	[$\frac{\mathbf{m}}{\mathbf{s}}$]	[-]	[10^-4m^2]	[10^-2 $\frac{\mathbf{m}}{\mathbf{s}^{\mathbf{2}}}$]
66,0	09,0	90	39,0	09,17	12,25	0,522	47,759	10,280
65,0	14,5	145	38,0	14,78	15,55	0,663	45,342	9,759
64,0	19,5	195	37,0	19,88	18,03	0,769	42,987	9,253
63,0	21,5	215	36,0	21,92	18,93	0,807	40,694	8,759
61,5	25,5	255	34,5	25,99	20,62	0,879	37,374	8,044
60,0	27,0	270	33,0	27,52	21,21	0,905	34,195	7,360
58,5	28,5	285	31,5	29,05	21,79	0,929	31,157	6,706
57,0	29,0	290	30,0	29,56	21,98	0,937	28,260	6,083
55,0	31,0	310	28,0	31,60	22,73	0,969	24,618	5,299
53,0	32,5	325	26,0	33,13	23,27	0,992	21,226	4,569
51,0	33,0	330	24,0	33,64	23,45	1,000	18,086	3,893
49,0	33,0	330	22,0	33,64	23,45	1,000	15,198	3,271
47,0	32,0	320	20,0	32,62	23,09	0,985	12,560	2,703
45,0	33,0	330	18,0	33,64	23,45	1,000	10,174	2,190
43,0	33,0	330	16,0	33,64	23,45	1,000	08,038	1,730
41,0	32,5	325	14,0	33,13	23,27	0,992	06,154	1,325
38,0	32,0	320	11,0	32,62	23,09	0,985	03,799	0,818
35,0	32,5	325	08,0	33,13	23,27	0,992	02,010	0,433
32,0	32,0	320	05,0	32,62	23,09	0,985	00,785	0,169
29,0	32,0	320	02,0	32,62	23,09	0,985	00,126	0,027
27,0	31,5	315	00,0	32,11	22,91	0,977	00,000	0,000

Tabela pomiarowa

V_śr = 21,52 $\frac{m}{s}$

V_max = 23,45 $\frac{m}{s}$

∆h = 450 Pa

ρ_m = 1000 $\frac{\text{kg}}{m^{3}}$

ρ = 1,2 $\frac{\text{kg}}{m^{3}}$

Przykładowe obliczenia:

1 mmH₂O = 10 Pa

Pd = $\frac{\rho V^{2}}{2}$ => V = $\sqrt{\frac{2Pd}{\rho}}$

V₁ = $\sqrt{\frac{2*90}{1,2}}$ = 12,25 $\frac{m}{s}$

Pd = ρ_m * h * g => h = $\frac{\text{Pd}}{\rho_{m}*g}$

h_{1 =} $\frac{90}{1000*9,81}$ = 9,17 * 10^-3m

($\frac{V}{V_{\max}}$ )₁ = $\frac{12,25}{23,45}$ = 0,522

A = $\frac{\pi D^{2}}{4}$

A₁ = $\frac{3,14*(78*10^{- 3})_{}^{2}}{4}$ = 47,759*10^-4 m

q_V = A * V_śr

q_V1 = 47,759*10^-4 * 21,52 = 10,280 $\frac{m^{3}}{s}$