Cours Bergen05print

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Introduction to Geostatistics































































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Centre de Géostatistique - EMP

Founded 1968 by:

Georges M

ATHERON

Director:

Jean-Paul C

HILÈS

Permanent staff:

14 research scientists

Funding (salaries):

60% by contract research,

,→

this conditions an application driven research































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CG: Main application fields

Petroleum exploration, mining

Environmental sciences, climatology

Health: epidemiology

Fisheries, demography . . .

Software products:

Isatis

, Heresim. . .

sold by Geovariances International (

www.geovariances.fr

)

Also:

Bioinformatics group (SVM, kernel methods)































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Geostatistics worldwide

Other groups:

Stanford (petroleum), Trondheim (petroleum), Calgary
(mining, petroleum), Brisbane (mining), Johannesburg
(mining), Valencia (hydrogeology),. . .

Main meetings:

International Geostatistics Conference:
1st in Rome (1975), . . . , 7th in Banff (2004)

−→

2008: Santiago de Chile

geoENV (european geostatistics conference for
environmental applications):
1st in Lisbon (1996),. . . , 5th in Neuchatel (2004)

−→

2006: Greece

Software:

R (

www.r-project.org

),

−→

www.ai-geostats.org































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Geostatistics

definition













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Geostatistics

is an application of
the Theory of

Regionalized Variables

(usually considered as realizations of

Random Functions

)

to geology and mining (fifties)

to natural phenomena in general (seventies)

(re-)integrated mainstream statistics (nineties)













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Concepts

Variogram: description of the spatial/temporal correlation of
a phenomenon

Kriging: optimal linear prediction method for estimating
values of a phenomenon at any location of a region
(

D. G. K

RIGE

)

Conditional Simulation: stochastic simulation of
realizations, conditional upon the data.













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Basic Statistics

concepts





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Center of mass

Seven weights

w

are hanging on a bar whose own weight is

negligible:

5

6

7

8

weight w

elementary weight v

center of mass





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Center of mass

The weights

w

are suspended at points:

z = 5, 5.5, 6, 6.5, 7, 7.5, 8,

The mass

w(z)

of the weights is

w(z) = 3, 4, 6, 3, 4, 4, 2.

The location

z

where the bar, when suspended, stays in

equilibrium is:

z =

1



P

k

w(z

k

)



7

X

k

=1

z

k

w(z

k

)







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Z

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Center of mass

Defining normed weights:

p(z

k

) =

w(z

k

)



P

k

w(z

k

)



with

P

k

p(z

k

) = 1

, we can write:

z =

7

X

k

=1

z

k

p(z

k

)







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Z

Z

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Center of mass

The weights

w(z

k

)

are subdivided into

n

elementary weights

v

α

:

5

6

7

8

weight w

elementary weight v

center of mass

with corresponding normed weights

p

α

= 1/n

:

z =

n

X

α

=1

z

α

p

α

=

1

26

26

X

α

=1

z

α

= 6.4







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Z



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Center of mass

The average squared distance to the center of mass

dist

2

(z) =

1

n

n

X

α

=1

(z

α

− z)

2

= .83

gives an indication about the dispersion of the around the center
of mass

z

.







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Z

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Histogram

5

6

7

8

mean m*

The mean value

m

?

of data

z

α

is equivalently,

m

?

=

1

n

n

X

α

=1

z

α







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Z

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Histogram

The average squared deviation from the mean is the variance

s

2

=

1

n

n

X

α

=1

(z

α

− m

?

)

2

Its square-root is called the standard deviation.

The normalized weights

p(z

k

)

are the frequencies of the

occurence of the values

z = 5, 5.5, 6, 6.5, 7, 7.5, 8

.

n

is the number of samples.







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Z



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Cumulative histogram

An alternate way to represent the frequencies of the values

z

is

to cumulate them from left to right:

Z

FREQUENCY

CUMULATIVE

1

2

3

4

5

6

7

8







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Z

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Probability distribution

Suppose we draw randomly values

z

from a set of values

Z

.

We call

Z

a random variable and

z

its realizations,

z ∈ R

.

The mathematical idealization of the cumulative histogram
is the probability distribution function

F (z)

defined as:

F (z) = P (Z < z)

The probability

P (Z < z)

indicates the theoretical frequency

of drawing a realization lower than a given value

z

.







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Z

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Probability density

We shall only consider differentiable distribution functions.

The derivative of the probability distribution function is the
probability density

p(z)

:

F (dz) = p(z) dz

Properties:

0 ≤ p(z) ≤ 1
Z

p(z) dz = 1







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Z



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Expected value

The idealization of the concept of mean value is the
mathematical expectation:

E



Z



=

Z

z ∈ R

z p(z) dz = m.

The expectation is a linear operator.
Let

a

,

b

be constants:

E



a



= a,

E



b Z



= b E



Z



,

so that

E



a + b Z



= a + b E



Z









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Z

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Variance

The second moment of the random variable

Z

is:

E



Z

2



=

Z

z ∈ R

z

2

p(z) dz

The variance

σ

2

is defined as:

var(Z) = E

h

Z − E



Z



2

i

= E



(Z − m)

2



= σ

2

Alternate expression:

multiplying out we get

var(Z) = E



Z

2

+ m

2

− 2mZ



and, as the expectation is a linear operator,

var(Z) = E



Z

2



− E



Z



2







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Covariance

Covariance

σ

ij

between

Z

i

and

Z

j

:

cov(Z

i

, Z

j

) = E



Z

i

− E



Z

i



· Z

j

− E



Z

j

 

= E



(Z

i

− m

i

) · (Z

j

− m

j

)



= σ

ij

where

m

i

and

m

j

are the means of the random variables.

Covariance of

Z

i

with itself:

σ

ii

= E



(Z

i

− m

i

)

2



= σ

2

i

Correlation coefficient:

ρ

ij

=

σ

ij

q

σ

2

i

σ

2

j







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Z

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Linear regression



















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Regression line

● ●

● ●

● ●

● ●

● ●

● ●

1

z

2

z

2

z

1

z * = a

+ b

● ●

● ●

● ●

● ●

● ●

● ●

● ●

1

2

m*

m*



















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Optimal regression line

Two variables with experimental covariance:

s

12

=

1

n

n

X

α

=1

(z

α

1

− m

?
1

) · (z

α

2

− m

?
2

)

The regression line is:

z

?

1

= a z

2

+ b

with slope

a

and intercept

b

.

Minimizing the quadratic distance:

dist

2

(a, b)

=

1

n

n

X

α

=1

(z

α

1

− a z

α

2

− b)

2

we get

a =

s

12

s

2

2

b = m

?

1

− a m

?

2



















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Optimal regression line

z

?

1

=

s

12

s

2

2

(z

2

− m

?
2

) + m

?
1

= m

?
1

+

s

1

s

2

r

12

(z

2

− m

?
2

)

At the minimum the squared distance is:

dist

2
min

(a, b) = s

2

1

1 − (r

12

)

2





















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Multiple linear regression







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Multivariate data set

The data matrix

Z

with

n

samples of

N

variables:

Samples

V ariables

z

11

. . . z

1i

. . . z

1N

..

.

..

.

..

.

z

α

1

. . . z

αi

. . . z

αN

..

.

..

.

..

.

z

n

1

. . . z

ni

. . . z

nN







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Matrix of means

Define a matrix

M

with the same dimension

n × N

as

Z

,

replicating

n

times in its columns the mean value of each

variable:

M

=

m

?

1

. . . m

?
i

. . . m

?
N

..

.

..

.

..

.

m

?

1

. . . m

?
i

. . . m

?
N

..

.

..

.

..

.

m

?

1

. . . m

?
i

. . . m

?
N







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Centered variables

A matrix

Z

c

of centered variables is obtained by subtracting

M

from the raw data matrix:

Z

c

=

Z

M







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Variance-covariance matrix

The matrix

V

of experimental variances and covariances is:

V

=

1

n

Z

>

c

Z

c

=

var(z

1

)

. . . cov(z

1

, z

j

) . . . cov(z

1

, z

N

)

..

.

. ..

..

.

cov(z

i

, z

1

)

. . .

var(z

i

)

. . . cov(z

i

, z

N

)

..

.

. ..

..

.

cov(z

N

, z

1

) . . . cov(z

N

, z

j

) . . .

var(z

N

)

=

s

11

. . . s

1j

. . . s

1N

..

.

. ..

..

.

s

i

1

. . .

s

ii

. . .

s

iN

..

.

. ..

..

.

s

N

1

. . . s

N j

. . . s

N N







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Multiple linear regression

For a regression of

z

0

on the

N

variables from

n

samples

we have the matrix equation

z

?
0

= m

0

+ (Z − M) a

The squared distance between

z

0

and the hyperplane is:

dist

2

(a) =

1

n

(z

0

− z

?
0

)

>

(z

0

− z

?
0

)

= var(z

0

) + a

>

Va

− 2 a

>

v

0

,

where

v

0

is the vector of covariances

between

z

0

and

z

i

, i = 1, . . . , N

.







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Z

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Minimizing the squared distance

The minimum is found for:

∂ dist

2

(a)

∂a

= 0

⇐⇒

2 Va − 2 v

0

= 0

⇐⇒

Va

= v

0

This system of linear equations:

var(z

1

)

. . . cov(z

1

, z

N

)

..

.

. ..

..

.

cov(z

N

, z

1

) . . .

var(z

N

)

a

1

..

.

a

N

=

cov(z

0

, z

1

)

..

.

cov(z

0

, z

N

)

has exactly one solution,
if the determinant of

V

is different from zero.

The squared distance at the minimum is:

dist

2
min

(a) = var(z

0

) − a

>

v

0







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Simple kriging



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Spatial data

Data points

x

α

and the estimation point

x

0

in a spatial domain

D

0

x

x

α

D



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Translation invariance

The expectation and the covariance are both assumed
translation invariant over the domain,
i.e. for any vector

h

between points

x

and

x

+h

:

E



Z(x+h)



= E



Z(x)



= m

cov



Z(x+h), Z(x)



= C(h)

The expectation

E



Z(x)



has the same value

m

at any point

x

of the domain

D

.

The covariance between any pair of locations
depends only on the vector

h

.



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Known mean

We assume the mean

m

is known

and build the estimator:

Z

?

(x

0

) = m +

n

X

α

=1

w

α



Z(x

α

) − m



i.e.

Z

?

(x

0

) − m =

n

X

α

=1

w

α



Z(x

α

) − m



which is implicitly without bias:

E

h

Z

?

(x

0

) − m

i

=

n

X

α

=1

w

α

E

h

Z(x

α

) − m

i

= 0



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Simple kriging equations

The kriging equations with known mean are simple:

n

X

β

=1

w

SK

β

C(x

α

−x

β

) = C(x

α

−x

0

)

for

α= 1, . . . , n

i.e.
the linear combination of weights with
the covariances between a data point
and the other data points
=
the covariance between that data point
and the point to estimate.

The variance of the Simple Kriging estimate is:

σ

2

SK

= σ

2

n

X

α

=1

w

SK

α

C(x

α

−x

0

)



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Simple kriging: a multiple linear regression

Simple kriging is a multiple linear regression between spatial
random variables.

Like:

Va

= v

0

,

we have:

Cw

= c

0

Writing out the equation system:

var(Z(x

1

))

. . . cov(Z(x

1

), Z(x

N

))

..

.

. ..

..

.

cov(Z(x

N

), Z(x

1

)) . . .

var(Z(x

N

))

w

1

..

.

w

N

=

cov(Z(x

0

), cov(Z(x

1

))

..

.

cov(Z(x

0

), Z(x

N

))



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Regionalized variables

and random function

















































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The concept of a Random Function

Consider a domain

D

with points

x

:

x

D

Let

Z(x)

be a random variable at a location

x

∈ D

.

The family of random variables

n

Z(x); x ∈ D

o

is called a Random Function.

















































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Regionalized Variable

The regionalized variable

z(x)

is the spatial variable of interest

(“reality”).

Data does not generally allow a deterministic reconstruction of
the regionalized variable.























The regionalized variable

z(x)

is considered as a realization

(draw) of a random function

Z(x)

.

For a given data set, different realizations containing the data
are equally plausible to represent the regionalized variable.

















































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Z

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Epistemological Problem

We possess data about only one realization:
how can we specify the random function?

Objective quantities

that describe the regionalized variable and

conventional parameters

that are constitutive of the model have

to be distinguished.

The quantities are estimated from data,

but the parameters are chosen.

−→

G













“Estimating and Choosing”

















































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Variogram

definition











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The Variogram

The vector

x

=

x

1

x

2



: coordinates of a point in 2D.

Let

h

be the vector separating two points:

h

D

x

x

β

α

We compare sample values

z

at a pair of points with:



z(x + h) − z(x)



2

2











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The Variogram Cloud

Variogram values are plotted against distance in space:

●●

●● ●

●●

● ● ●

● ●

● ●

● ●

● ●

● ●

2

2

|h|

| z(t+h) - z(t) |











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The Experimental Variogram

Averages within distance (and angle) classes

k

are computed:

●●

●● ●

●●

● ● ●

● ●

● ●

● ●

● ●

● ●

1

2

3

4

5

6

7

8

9

h

h

h h h h h h

h

|h|

γ∗

(h )

k











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The Theoretical Variogram

A theoretical model is fitted:

γ

(h)

|h|











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Intrinsic Hypothesis

The first two moments of the

increments

are assumed stationary

(translation-invariant):

the expectation does not depend on

x

E

h

Z(x+h) − Z(x)

i

= 0

the variance depends only on

h

var

h

Z(x+h)−Z(x)

i

= 2 γ(h)

This type of stationarity is called

intrinsic

.

,→

The stationarity of the increments does not imply the

stationarity of

Z

.











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Definition of the Variogram

By the intrinsic hypothesis:

γ(h) =

1
2

E

h 

Z(x+h) − Z(x)



2

i

Properties

- zero at the origin

γ(0) = 0

- positive values

γ(h) ≥ 0

- even function

γ(h) = γ(−h)

Regionalized variable

Behavior at the origin









←→

continuous and differentiable









←→

not differentiable







←→

discontinuous











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Variogram and Covariance Function

The covariance function is defined as:

C(h) = E

h 

Z(x) − m



·



Z(x+h) − m

 i

where

stationarity of the first two moments

of

Z

is assumed.

A variogram can be constructed from any covariance function:

γ(h) = C(0) − C(h)

Conversely, however, only if the variogram is

bounded

does a

corresponding covariance function

C(h)

exist.

The variogram characterizes a larger class of random functions.
This is why it is preferred in geostatistics.











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Variogram

examples











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Z

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Power variogram

γ(h) = |h|

p

,

0 < p ≤ 2

Power model

DISTANCE

VARIOGRAM

-4

-2

0

2

4

0

1

2

3

4

5

p=1.5

p=1

p=0.5











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Spherical covariance function

C(h) =

 3

2

|h|

a

1
2

|h|

3

a

3



|h|≤a











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Exponential covariance function

C(h) = exp



|h|

a













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Gaussian covariance function

C(h) = exp



|h|

2

a

2













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Cardinal sine covariance function

C(h) =

sin



|h|

a



|h|

a











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Geometric anisotropy

of the variogram





















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Geometric anisotropy

In practice the range of the variogram may change depending
on the direction:

h

1

h

2

1

h’

2

h’

Correction:

rotation

h

0

= Qh

of angle

θ

where

Q

=

 cos θ sin θ

− sin θ cos θ



linear transformation of the coordinates

h

0

= (h

0

1

, h

0

2

)





















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Rotation in 3D

In 3D the rotation is obtained by a composition of elementary
rotations:

Q

=

cos θ

3

sin θ

3

0

− sin θ

3

cos θ

3

0

0

0

1

1

0

0

cos θ

2

sin θ

2

0

− sin θ

2

cos θ

2

0

cos θ

1

sin θ

1

0

− sin θ

1

cos θ

1

0

0

0

1

where

θ

1

,

θ

2

,

θ

3

are Euler’s angles.





















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2D example: Ebro river vertical section

-10.

-5.

0.

Ebro river (Kilometer)

-6.

-5.

-4.

-3.

-2.

-1.

0.

Depth (Meter)

185 Hydrolab Surveyor III conductivity measurements





















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2D conductivity variogram model

D1

D2

M1

M2

0.

1.

2.

3.

4.

5.

6.

Distance (D1: km; D2: m)

0.

250.

500.

750.

1000.

1250.

Variogram : CONDUCTIVITY

Experimental variogram for D1=horizontal, D2=vertical.

Anisotropic cubic variogram model in both directions (M1, M2).

Abscissa scale: kilometers for D1 and meters for D2.





















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Z

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Behavior at the origin

of the variogram









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Ebro river:

water samples

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

Distance from mouth (km)

-6.

-5.

-4.

-3.

-2.

-1.

0.

Depth (m)

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

-6.

-5.

-4.

-3.

-2.

-1.

0.

Depth (m)

47 water samples (top)

185 conductivity values (bottom)









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Nitrate variogram: which behavior at origin?

D1

D2

M1

M2

CUBIC

0.

1.

2.

3.

Lag (RED: m; BLACK: km)

0.

1000.

2000.

3000.

Variogram: NITRATE

D1

D2

M1

M2

EXPONENTIAL

0.

1.

2.

3.

Lag (RED: m; BLACK: km)

0.

1000.

2000.

3000.

Variogram: NITRATE

Nitrate experimental variogram with two alternate models.









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Cubic variogram: conditional simulations

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

-4.

-3.

-2.

-1.

0.

Depth (m)

>=124.8

117

109.2

101.4

93.6

85.8

78

70.2

62.4

54.6

46.8

39

31.2

23.4

15.6

7.8

<0
M

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

Distance from mouth (km)

-4.

-3.

-2.

-1.

0.

Depth (m)

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

-4.

-3.

-2.

-1.

0.

Depth (m)









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Exponential model: conditional simulations

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

-4.

-3.

-2.

-1.

0.

Depth (m)

>=124.8

117

109.2

101.4

93.6

85.8

78

70.2

62.4

54.6

46.8

39

31.2

23.4

15.6

7.8

<0
M

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

-4.

-3.

-2.

-1.

0.

Depth (m)

-15.0

-12.5

-10.0

-7.5

-5.0

-2.5

Distance from mouth (km)

-4.

-3.

-2.

-1.

0.

Depth (m)









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Kriging of the mean

of a random function





















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Spatially Correlated Data

Sample locations

x

α

in a geographical domain:

With spatial correlation we need to consider that:

sample points have a different number of immediate
neighbors,

distances to neighboring points play a role.

How should samples be weighted in an optimal way?





















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Estimation of the Mean Value

Using the formula of the arithmetic mean:

M

?

=

1

n

n

X

α

=1

Z(x

α

)

all samples get the same weight:

1

n

We rather need an estimator:

M

?

=

n

X

α

=1

w

α

Z(x

α

)

with weights

w

α

reflecting the spatial correlation.





















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Stationary random function

We assume translation-invariance of mean and covariance:

∀ x ∈ D :

E

h

Z(x)

i

= m;

∀ x

α

, x

β

∈ D :

C(x

α

, x

β

) = C(x

α

−x

β

).













 













The estimation error in our statistical model:

M

?

|

{z

}

estimated value

m

| {z }

true value

should be zero, on average:

E

h

M

?

− m

i

= 0





















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No bias

No bias is obtained using weights of unit sum:

n

X

α

=1

w

α

= 1

Consider:

E

h

M

?

− m

i

= E

h

n

X

α

=1

w

α

Z(x

α

) − m

i

=

n

X

α

=1

w

α

E

h

Z(x

α

)

i

|

{z

}

m

−m

= m

n

X

α

=1

w

α

| {z }

1

−m

=

0





















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Z

background image

Variance of the estimation error

The variance

σ

2

E

of the estimation error is:

var(M

?

− m) = E

h

(M

?

− m)

2

i

E

h

M

?

− m

i

2

|

{z

}

0

= E

h

M

?2

− 2 mM

?

+ m

2

i

=

n

X

α

=1

n

X

β

=1

w

α

w

β

E

h

Z(x

α

) Z(x

β

)

i

−2 m

n

X

α

=1

w

α

E

h

Z(x

α

)

i

|

{z

}

m

+m

2

σ

2

E

=

n

X

α

=1

n

X

β

=1

w

α

w

β

C(x

α

− x

β

)





















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Minimal estimation variance

We want weights

w

α

that produce a minimal estimation variance:

minimum of

var(M

?

− m)

subject to

n

X

α

=1

w

α

= 1





















The objective function

ϕ

has

n+1

parameters:

ϕ(w

1

, . . . , w

n

, µ) = var(M

?

− m) − 2 µ



n

X

α

=1

w

α

− 1



with

µ

a Lagrange multiplier. Setting partial derivatives to zero:

∀α :

∂ϕ(w

1

, . . . , w

n

, µ)

∂w

α

= 0,

∂ϕ(w

1

, . . . , w

n

, µ)

∂µ

= 0





















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Kriging equations

The method of Lagrange yields the equations for
the optimal weights

w

KM

α

of the kriging of the mean:


n

X

β

=1

w

KM

β

C(x

α

− x

β

) − µ

KM

= 0

for

α = 1, . . . , n

n

X

β

=1

w

KM

β

= 1

The variance at the minimum:

σ

2

KM

= µ

KM

is equal to the Lagrange multiplier.





















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Case of no autocorrelation

When the covariance model is a pure nugget-effect:

C(x

α

− x

β

) =

 σ

2

if

x

α

= x

β

0

if

x

α

6= x

β

the kriging of the mean system simplifies to:


w

KM

α

σ

2

= µ

KM

for

α = 1, . . . , n

n

X

β

=1

w

KM

β

=

1

The solution weights are all equal:

w

KM

α

=

1

n

M

?

=

1

n

n

X

α

=1

Z(x

α

)

the arithmetic mean!

µ

KM

= σ

2

KM

=

1

n

σ

2





















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Ordinary Kriging

at a point in the domain



















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Estimation at a Point

Sample locations

x

α

(dots)

in a domain

D

:

x

0

We wish to estimate a value

Z

?

at a point

x

0

.



















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Ordinary kriging

The estimate

Z

?

is a weighted average of data values

Z(x

α

)

:

Z

?

(x

0

) =

n

X

α

=1

w

α

Z(x

α

)

with

n

X

α

=1

w

α

= 1

The weights

w

OK

α

of the Best Linear Unbiased Estimator (BLUE)

are solution of the system:


n

X

β

=1

w

OK

β

γ(x

α

−x

β

) + µ

OK

=

γ(x

α

−x

0

)

∀α

n

X

β

=1

w

OK

β

=

1

Minimal variance:

σ

2

OK

= µ

OK

+

n

X

α

=1

w

OK

α

γ(x

α

−x

0

)



















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Cross-validation

leaving one out and reestimating it













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Cross-validation

Comment:

the sound way to cross-validate is to leave out half

of the data locations and to re-estimate them from the other
half : this requires many data! For that reason it is often done in
the following way (implemented in sotware packages). . .

A data value

Z(x

α

)

is left out and a value

Z

?

(x

[α]

)

is estimated at

location

x

α

by ordinary kriging.

The notation

[α]

means that the sample at

x

α

has not been used

for estimating

Z

?

(x

[α]

)

.

The difference between the data value and the estimated value:

Z(x

α

) − Z

?

(x

[α]

)

gives an indication of how well the data value fits into the
neigborhood of the surrounding data values.













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Average cross-Validation error

If the average of the cross-validation errors is not far from zero:

1

n

n

X

α

=1

Z(x

α

) − Z

?

(x

[α]

)

!

= 0

then there is no systematic bias.

A negative (positive) average error represents
systematic overestimation (underestimation).













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Z

background image

Standardized cross-validation error

The kriging standard deviation

σ

K

represents the error predicted

by the model.

Dividing the cross-validation error by

σ

K

allows to compare the

magnitudes of both errors:

Z(x

α

) − Z

?

(x

[α]

)

σ













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Average squared Standardized Errors

If the average of the squared standardized cross-validation
errors is not far from one:

1

n

n

X

α

=1

Z(x

α

) − Z

?

(x

[α]

)

!

2

σ

2

= 1

then the actual estimation error is equal on average to the error
predicted by the model.

This quantity gives an idea of the adequacy of the model and of
its parameters.













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Mapping with kriging

on a regular grid

with irregularly spaced data

W

W



















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Kriging for interpolation

Kriging is an estimation method.

It is not the quickest method to make an interpolation on a
regular grid for generating a map.

Its advantages are:

Kriging integrates the knowledge
gained from analysing the spatial structure:
the variogram.

Kriging interpolates exactly: when a sample value is
available at the location-of-interest, the kriging solution is
equal to that value.

Kriging provides an indication of the estimation error: the
kriging variance.

W

W



















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Generating a map

A regular grid is defined by the computer and
at each node of this grid a value is kriged.

x

0

Afterwards a graphical representation of this grid is performed,
as a raster of colour squares, as an isoline map, as a bloc
diagram. . .

W

W



















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Moving Neighborhood

If all data are used:

this is called a unique neighborhood.

Using a subset of close data points:

a moving neighborhood.

x

0

To choose the size of the moving neighborhood, the range of the
variogram can give an indication.

W

W



















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Kriging weights

The shape of the kriging weights



















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Kriging weights

Nugget-effect model

σ

2

OK

= 1.25

25%

25%

25%

25%

L



















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Isotropic variogram

Spherical model with range a/L = 2

σ

2

OK

= .84

9.4%

9.4%

40.6%

40.6%

L

Gaussian model with range a/L = 1.5

σ

2

OK

= .30

49.8

49.8%

0.2%

0.2%

L



















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Geometric anisotropy

Spherical with isotropic range

25%

25%

25%

25%

L

Spherical with horizontal a/L = 1.5 and vertical a/L = .75

L

17.6%

17.6%

32.4%

32.4%



















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background image

Relative position of samples

σ

2

OK

= .45

σ

2

OK

= .48

33.3%

33.3%

33.3%

25.9%

37.1%

37.1%

The left configuration gives a more reliable estimate.



















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The screen effect

Spherical model with range a/L = 2

σ

2

OK

= 1.14

34.4%

A

65.6%

B

σ

2

OK

= 0.87

A

B

C

49.1%

48.2%

2.7%

Adding the sample C screens off the sample B.



















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Nested variogram

and corresponding linear model

of the random function



















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Nested Variogram Model

A nested variogram

γ(h)

is composed of

a sum of elementary variograms

γ

u

(h)

with

u = 0, . . . , S

:

γ(h) = γ

0

(h) + . . . + γ

S

(h) =

S

X

u

=0

γ

u

(h)

Each variogram

γ

u

(h)

is build up with a normed variogram

g

u

(h)

multiplied with a coefficient

b

u

(sill, slope):

γ(h) =

S

X

u

=0

b

u

g

u

(h)



















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Example: Arsenic in soil (Loire, France)

310.

315.

320.

325.

330.

335.

340.

270.

275.

280.

285.

river

Loire

35

×

25 km

2

region. Dots are proportional to sample value.



















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Example: Nested Variogram Model

A nugget-effect (nug) and two spherical (sph) structures:

γ(h) =

b

0

nug

(h) +

b

1

sph

(h,

a

1

) +

b

2

sph

(h,

a

2

)

0.

1.

2.

3.

4.

5.

6.

7.

8.

9.

10.

11.

0.0

0.5

1.0

nugget

long range

short range

(h)

γ

h



















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Nested Covariance Function

C(h) =

S

X

u

=0

C

u

(h) =

S

X

u

=0

b

u

ρ

u

(h)

where

ρ

u

(h)

are correlation functions.

The

ρ

u

(h)

characterize the spatial correlation

at

different scales

of index

u

.

The coefficents

b

u

represent a decomposition of

the

total variance

σ

2

into variances at different spatial scales:

C(0) = σ

2

=

S

X

u

=0

b

u



















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Regionalization Model

Z(x)

built up with

uncorrelated components

Y

u

(x)

of zero mean, with covariance functions

C

u

(h)

.

Example:

Z(x) = Y

1

(x) + Y

2

(x) + m

with

Y

1

⊥Y

2

The covariance function of

Z(x)

is nested:

C(h) = C

1

(h) + C

2

(h)















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Linear Model with

S + 1

components

Z(x) =

S

X

u

=0

Y

u

(x)

+ m

with

Y

u

⊥Y

v

for

u 6= v

Corresponding

nested

covariance model:

C(h) =

S

X

u

=0

C

u

(h)

=

S

X

u

=0

b

u

ρ

u

(h)

Can components

Y

u

be

extracted

from samples

Z(x

α

)

?















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Z

background image

Kriging Spatial Components

A component

Y

1

(x)

at

x

0

is estimated from

n

data:

Y

?

1

(x

0

) =

n

X

α

=1

w

α

Z(x

α

)

“No bias” with

n

X

α

=1

w

α

= 0

:

this filters the mean

m

Minimizing the “estimation variance”:


n

X

β

=1

w

1

β

C(x

α

−x

β

) − µ

1

=

C

1

(x

α

−x

0

)

for

α= 1, . . . , n

n

X

β

=1

w

β

=

0















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Z

Z

background image

Example: Short-range Component of As

310.

315.

320.

325.

330.

335.

340.

270.

275.

280.

285.















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background image

Example: Long-range Component of As

310.

315.

320.

325.

330.

335.

340.

270.

275.

280.

285.















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Z

background image

Demographic application

fertility data









W





W

W









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Z

background image

Demographic application: fertility 1990

43°

44°

45°

46°

47°

48°

49°

50°

51°

250 km

Communes de France

Nb of women per "commune"

Mean annual fertility ’90

0

50

100

150

100

500

5000

10000

25000

50000

5e+05

FERT500 class

Data provided by INSEE (

www.insee.fr

)









W





W

W









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Z



background image

Variograms: class 100-500 women / commune

D1

D2

D3

D4

0.

100.

200.

300.

Distance (km)

0.

25.

50.

75.

100.

Variogram : FERT500

D1

M1

0.

100.

200.

300.

400.

Distance (km)

0.

10.

20.

30.

40.

50.

60.

70.

80.

90.

100.

110.

Variogram : FERT500

long range

short range









W





W

W









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Z

background image

Kriging: short range effect only

D1

M1

0.

100.

200.

300.

400.

Distance (km)

0.

10.

20.

30.

40.

50.

60.

70.

80.

90.

100.

110.

Variogram : FERT500

short range

-100.

0.

100.

200.

300.

400.

500.

600.

700.

800.

UTM (Km)

4700.

4800.

4900.

5000.

5100.

5200.

5300.

5400.

5500.

5600.

UTM (Km)

Fert500 estimation

>=9.96

9.18

8.4

7.62

6.84

6.06

5.28

4.5

3.72

2.94

2.16

1.38

0.6

-0.18

-0.96

-1.74

-2.52

-3.3

-4.08

-4.86

-5.64

-6.42

-7.2

-7.98

-8.76

-9.54

-10.32

-11.1

-11.88

-12.66

-13.44

-14.22

<-15









W





W

W









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Z

background image

Kriging

-100.

0.

100.

200.

300.

400.

500.

600.

700.

800.

UTM (Km)

4700.

4800.

4900.

5000.

5100.

5200.

5300.

5400.

5500.

5600.

UTM (Km)

FERT500long_range

>=60

59.2188

58.4375

57.6562

56.875

56.0938

55.3125

54.5312

53.75

52.9688

52.1875

51.4062

50.625

49.8438

49.0625

48.2812

47.5

46.7188

45.9375

45.1562

44.375

43.5938

42.8125

42.0312

41.25

40.4688

39.6875

38.9062

38.125

37.3438

36.5625

35.7812

<35

-100.

0.

100.

200.

300.

400.

500.

600.

700.

800.

UTM (Km)

4700.

4800.

4900.

5000.

5100.

5200.

5300.

5400.

5500.

5600.

UTM (Km)

Fert500 estimation

>=65.2

64.1

63

61.9

60.8

59.7

58.6

57.5

56.4

55.3

54.2

53.1

52

50.9

49.8

48.7

47.6

46.5

45.4

44.3

43.2

42.1

41

39.9

38.8

37.7

36.6

35.5

34.4

33.3

32.2

31.1

<30

Long range effect

Short + long range









W





W

W









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Z



background image

Kriging with external drift

































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Z

background image

Drift

Translation-invariant drift:

polynomials, trigonometric functions

External Drift:

an auxiliary variable known everywhere

































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Z

Z

background image

External drift method



1.

Auxiliary variable

s(x)

known everywhere in the domain

D

.

2.

The relation to the variable of interest is linear:

E

h

Z(x)

i

= b

0

+ b

1

s(x)

































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Z

Z

Z

background image

External Drift method

Z

?

(x

0

) =

n

X

α

=1

w

α

Z(x

α

)

E

h

Z

?

(x

0

)

i

=

n

X

α

=1

w

α



b

0

+ b

1

s(x

α

)



































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Z

Z



background image

Constraint: no bias

The constraint

n

X

α

=1

w

α

= 1

has the effect that the coefficients

b

0

and

b

1

are filtered out:

E

h

Z

?

(x

0

)

i

= E

h

Z(x

0

)

i

=⇒

b

0

+ b

1

n

X

α

=1

w

α

s(x

α

) = b

0

+ b

1

s(x

0

)

=⇒

n

X

α

=1

w

α

s(x

α

) = s(x

0

)

































V

WYX

Z

Z

background image

Interpolation of external drift

This second constraint:

n

X

α

=1

w

α

s(x

α

) = s(x

0

)

generates weights

w

α

which interpolate exactly

s(x)

.

































V

WYX

Z

Z

background image

Kriging System with linear and external drift


n

X

β

=1

w

β

C(x

α

−x

β

) + µ

0

+ µ

1

x

1
α

+ µ

2

x

2
α

+ µ

3

s(x

α

) = C(x

α

−x

0

), ∀α

n

X

β

=1

w

β

= 1

n

X

β

=1

w

β

x

1
β

= x

1

0

(longitude)

n

X

β

=1

w

β

x

2
β

= x

2

0

(latitude)

n

X

β

=1

w

β

s(x

β

) = s(x

0

)

(external drift)

































V

WYX

Z

Z



background image

Kriging temperature

with elevation as external drift



V

WYX

Z

Z

background image

Temperature Data















temperature conditions the growth of plants







Scotland (without the Shetland and Orkney Islands)





average January temperatures (1961-1980)











146 sites, all below 400 m altitude

















Ben Nevis, 1344 m













at 3035 nodes of a regular grid





















1272 m

Reference:

Int. J. Clim., 14, 77–91, 1994



V

WYX

Z

Z

background image

January temperature vs latitude / longitude

















 























 



 

   

Scatter diagrams of temperature with latitude and longitude:

there is a systematic decrease from west to east, while there is

not much trend in the north-south direction.



V

WYX

Z

Z



background image

E-W and N-S temperature variograms























  



The model is fitted in the direction without drift



V

WYX

Z

Z

background image

Kriging mean January temperature



















































V

WYX

Z



background image

Temperature vs elevation

















 



   

     

Coastal influence below 50m, then linear relation.

Temperatures only available below 400m.



V

WYX

Z



Z

background image

Kriging temperature with elevation as drift

























































V

WYX

Z





background image

Temperature estimates vs elevation















 

   

  

The estimated values above 400m are linearly extrapolated

outside the range of the data !



V

WYX

Z



background image

Estimated external drift coefficient

b

?
1

=

n

X

α

=1

w

α

Z(x

α

)


n

X

β

=1

w

β

C(x

α

−x

β

) + µ

0

+ µ

1

x

1
α

+ µ

2

x

2
α

+ µ

3

s(x

α

) =

0

, ∀α

n

X

β

=1

w

β

=

0

n

X

β

=1

w

β

x

1
β

=

0

(longitude)

n

X

β

=1

w

β

x

2
β

=

0

(latitude)

n

X

β

=1

w

β

s(x

β

) =

1

(external drift)



V

WYX

Z



background image

Estimated external drift coefficient



















































V

WYX

Z





background image

Conditional simulation























V

WYX

Z



background image

Conditional simulation vs Kriging























V

WYX

Z



background image

Change of support

geostatistical simulation of O

3























V

WYX

Z





background image

CASE STUDY: Geostatistical simulation of O

3















of realizations a lognormal random function







800

×

600 Km

2









1

×

1 Km

2















with a range of 50 Km























V

WYX

Z



background image

Simulation of Ozone: 1

×

1 Km

2

support

0. 100.

200.

300.

400.

500.

600.

700.

Km

0.

100.

200.

300.

400.

500.

Km

O3: 1x1km2

>=96
90
84
78
72
66
60
54
48
42
36
30
24
18
12
6
<0

ug/m3























V

WYX

Z

background image

Simulation of Ozone: 10

×

10 Km

2

support

100.

200.

300.

400.

500.

600.

700.

Km

100.

200.

300.

400.

500.

Km

O3: 10x10km2

>=96
90
84
78
72
66
60
54
48
42
36
30
24
18
12
6
<0

ug/m3























V

WYX

Z

Z

background image

Simulation of Ozone: 20

×

20 Km

2

support

100.

200.

300.

400.

500.

600.

700.

Km

100.

200.

300.

400.

500.

Km

O3: 20x20km2

>=96
90
84
78
72
66
60
54
48
42
36
30
24
18
12
6
<0

ug/m3























V

WYX

Z



background image

Simulation of Ozone

0.

100.

200.

O3 (ug/m3)

0.0

0.1

0.2

0.3

Frequencies

SUPPORT: 1x1 Km2

Nb Samples: 480000

Minimum: 0.0

Maximum: 246.3

Mean: 6.7

Std. Dev.: 10.2

0. 10. 20. 30. 40. 50. 60. 70.

O3 (ug/m3)

0.000

0.025

0.050

0.075

0.100

0.125

Frequencies

SUPPORT: 20x20 Km2

Nb Samples: 1131

Minimum: 0.2

Maximum: 72.0

Mean: 6.7

Std. Dev.: 7.9

Increasing the support

: the means are equal,

but the extremes and the

variance

are reduced























V

WYX

Z

background image

Simulation of Ozone

D1

D2

0.

50.

100.

150.

200.

Distance (Km)

0.

25.

50.

75.

100.

Variogram: O3

SUPPORT

1x1 Km2

D1

D2

0.

50.

100.

150.

200.

Distance (Km)

0.

10.

20.

30.

40.

50.

60.

70.

Variogram: O3

SUPPORT

20x20 Km2

Increasing the support

:

the

range

increases























V

WYX

Z

background image

Simulation of Ozone

40. 50. 60. 70. 80. 90. 100.

110.

120.

O3 cutoff (ug/m3)

0.

50.

100.

150.

Mean O3 over cutoff (ug/m3)

black = 1x1Km

blue = 10x10Km

red = 20x20Km























V

WYX

Z



background image

Simulation of Ozone

40. 50. 60. 70. 80. 90. 100.

110.

120.

O3 cutoff (ug/m3)

0.0

0.5

1.0

1.5

Proportion above cutoff (%)

black = 1x1Km2

blue = 10x10Km2

red = 20x20Km2























V

WYX

Z

background image

Change of support

concept











W

W





V

WYX

Z

background image

TOPIC: The Support of a Random Function

3D

Volumes

2D

v

V

t

T

1D

Surfaces

s

S

Soil pollution

Industrial hygienics

Time intervals

Mining











W

W





V

WYX

Z



background image

The Effect of Changing the Support

Distribution of samples on small volumes (cm

3

) is different from

that of model output averages over large blocks (m

3

):

Z

mean

frequency

blocs

samples

The mean of both distributions is the same,

the distribution of the block values is narrower.











W

W





V

WYX

Z

background image

Neglecting the Support Effect

We are often interested in what is above a threshold:

threshold

overestimation!

Neglecting the

support effect

may lead to a systematic

over-estimation. . .











W

W





V

WYX

Z

background image

Neglecting the Support Effect

. . . or to systematic under-estimation:

threshold

underestimation!

A good estimation method should incorporate
a

change of support

model.











W

W





V

WYX

Z

Z

background image

Kriging of a Block average

(centered at a point in the domain)















V

WYX

Z



background image

Estimation of a block value

Sample locations

x

α

(dots)

in a domain

D

:

V

0

We wish to estimate the spatial average

Z

?

for a block

V

0

.















V

WYX

Z

background image

Block Kriging

The block value

Z

?

(V

0

)

is estimated as a weighted average of

the data values

Z(x

α

)

:

Z

?

(V

0

) =

n

X

α

=1

w

α

Z(x

α

)

with

n

X

α

=1

w

α

= 1

The optimal weights

w

OK

α

are obtained from the sytem:


n

X

β

=1

w

OK

β

γ(x

α

−x

β

) + µ

OK

=

γ(V

0

, x

α

)

∀α

n

X

β

=1

w

OK

β

=

1

Kriging variance:

σ

2

OK

= µ

OK

− γ(V

0

, V

0

) +

n

X

α

=1

w

OK

α

γ(V

0

, x

α

)















V

WYX

Z

background image

Block kriging with non-point data

In applications the data can be averaged on blocks

V

α

.

We then use average variograms between these blocks:

γ



V

α

, V

β



=

1

|V

α

| |V

β

|

Z

x

∈V

α

Z

y

∈V

β

γ(x − y) dx dy

This requires the knowledge of the point variogram.

V

0

v

α















V

WYX

Z



background image

Change of support

risk of exceeding ozone alert level







W

W





V

WYX

Z

background image

Change of support

The variability of spatial or temporal data depends on the
averaging volume/interval(= the

support

)

Increasing support, the variability decreases
(reduction of variance, extremes...)

Observations are on

point

support as compared to the

cells

of a numerical model.

End-users are often interested by a support of different
(intermediate) size

−→

blocks

It is thus necessary to describe statistically how variability
changes as a function of support.

If the distribution is monomodal and not too asymmetrical,
an affine correction may suffice. Otherwise, non-linear
geostatistics or geostatistical simulation are needed

Applications:

data aggregation, estimation of small block

statistics, downscaling. . .







W

W





V

WYX

Z

background image

Ozone in Paris on 17 july 1999 at 15h UTC

P6

P7

P13

P18

Garches

Gennevilliers

Neuilly

Aubervilliers

Tremblay

Vitry

Melun

Mantes

Montgeron

RUR_SE

RUR_E

RUR_SO

RUR_O

RUR_NO

RUR_NE

1.4°

1.6°

1.8°

2.2°

2.4°

2.6°

2.8°

3.2°

48.2°

48.4°

48.6°

48.8°

49°

49.2°

49.4°

50 km

Airparif stations and Chimere grid

19 Airparif stations;

25 × 25

grid with

cells of size 6

×

6 km

2







W

W





V

WYX

Z



background image

Air quality regulations

Two ozone thresholds refering to a support of

1 hour

:

−→

Swiss alert level:

120

µ

g/m

3

−→

European alert level:

180

µ

g/m

3

Time support is always specified, yet regulations do not contain
any indication about the

spatial support

!

Suppose the air quality experts agree on the following

spatial decision support

:

a block of

1 × 1

km

2

size

(instead of the CHIMERE

6 × 6

km

2

cell).

We need to model the

point-block-cell

change of support.







W

W





V

WYX

Z

background image

Discrete Gaussian point-block model

(due to Georges M

ATHERON

, 1976)

x

is a point randomly located in a block

v

.

E



Z(x)

| Z(v)



= Z(v),

is known as Cartier ’s relation.

For a Gaussian

point

anamorphosis (

station data

),

Z(x) = ϕ(Y (x)) =

X

k

=0

ϕ

k

k!

H

k

(Y (x))

with Hermite polynomials

H

k

and coefficients

ϕ

k

,

the

block

anamorphosis

ϕ

v

(Y (v))

comes as:

ϕ

v

(Y (v)) = E



ϕ(Y (x)) | Y (v)



=

X

k

=0

ϕ

k

k!

r

k

H

k

(Y (v)).







W

W





V

WYX

Z



background image

Point-block-cell correlations

The Gaussian block anamorphosis is:

ϕ

v

(Y (v)) =

X

k

=0

ϕ

k

k!

r

k

H

k

(Y (v)),

with

r

being the

point-block

coefficient

(

0 ≤ r ≤ 1

).

r

can be computed from the block dispersion variance

(which is calculated from the station data variogram):

var(Z(v)) = var(ϕ

v

(Y (v))) =

X

k

=1

ϕ

2

k

k!

r

2k

We get in the same way a

point-cell

coefficient

r

0

.

And finally the

block-cell

coefficient

r

vV

= r

0

/r

.







W

W





V

WYX

Z



Z

background image

Uniform conditioning

It consists in taking the conditional expectation of a
non-linear function of blocks knowing the cell value
containing them.

The

proportion of blocks

v ∈ V

0

above the threshold

z

c

knowing the cell value

Z(V

0

)

is:

E



Z

(v)≥z

c

| Z(V

0

)



= 1 − G

 y

c

r

vV

Y (V

0

)

1 −

r

vV

2



.

G

is the Gaussian distribution.







W

W





V

WYX

Z





background image

Variogram of Airparif measurements

0.

10.

20.

30.

40.

50.

60.

Distance (Kilometer)

0.

1000.

2000.

3000.

4000.

Variogram : Ozone_17JUL15H

0.

10.

20.

30.

40.

50.

60.

Distance (Kilometer)

0.

250.

500.

750.

1000.

Variogram : Ozone_17JUL15H

Nugget-effect + cubic model.

Sill = variance.







W

W





V

WYX

Z



background image

Anamorphosis of Airparif measurements

-2.

-1.

0.

1.

2.

Gaussian values

100.

125.

150.

175.

200.

225.

Ozone

r=.97

-2.

-1.

0.

1.

2.

Gaussian values

100.

125.

150.

175.

200.

225.

Ozone

r’=.72

Anamorphosis of

block

values (r=.97)

close to the anamorphosis of

point

values.

Anamorphosis of

cell

values (r’=.72).







W

W





V

WYX

Z



background image

Histograms

120.

130.

140.

150.

160.

170.

180.

190.

200.

210.

Ozone

0.

10.

20.

30.

Frequencies (%)

Histograms of blocks (

blue

) and cells (

red

)

on the basis of the change-of-support model.







W

W





V

WYX

Z





background image

Proportion of values above threshold

120.

130.

140.

150.

160.

170.

180.

190.

200.

210.

Ozone

0.

10.

20.

30.

40.

50.

60.

70.

80.

90.

100.

Proportion above alert level

Proportions of blocks (

blue

) and cells (

red

).

Depending on the threshold, the difference can be important !







W

W





V

WYX

Z



background image

Uniform conditioning by CHIMERE

0.1

0.1

0.2

0.2

0.3

0.3

0.3

0.4

0.4

0.4

0.5

0.5

0.5

0.6

0.6

0.6

0.7

0.7

0.8

0.8

0.9

0.9

1.4°

1.6°

1.8°

2.2°

2.4°

2.6°

2.8°

3.2°

48.2°

48.4°

48.6°

48.8°

49°

49.2°

49.4°

50 km

UC 120: CHIMERE + Airparif stations

Exceedance probabilities for

1 × 1

km

2

support

with the Swiss threshold of

120

µ

g/m

3







W

W





V

WYX

Z



background image

Uniform conditioning by CHIMERE

0.1

0.1

0.2

0.2

0.3

0.3

0.4

0.4

0.4

0.5

0.5

0.6

0.6

0.7

0.7

0.8

0.9

1.4°

1.6°

1.8°

2.2°

2.4°

2.6°

2.8°

3.2°

48.2°

48.4°

48.6°

48.8°

49°

49.2°

49.4°

50 km

UC 180: CHIMERE + Airparif stations

Exceedance probabilities for

1 × 1

km

2

support

with the European threshold of

180

µ

g/m

3







W

W





V

WYX

Z





background image

Precipitation in SE Norway

geostatistical downscaling









W





W







V

WYX

Z



background image

Histogram of precipitation: July 2001





































W





W







V

WYX

Z

background image

Variogram of precipitation









W





W







V

WYX

Z

Z

background image

Block and cell anamorphosis

r=.7

r=.365

10

×

10km

2

blocks

NCEP cells









W





W







V

WYX

Z



background image

Reconstructed histograms

10

×

10 km

2

blocks

101

×

212km

2

NCEP cells









W





W







V

WYX

Z

background image

Proportion above threshold

10

×

10km

2

blocks

NCEP cells

A threshold of 100mm will be used









W





W







V

WYX

Z

background image

Proportion blocks >100mm within NCEP cells









W





W







V

WYX

Z



background image

NCEP cells and station values

Color codes:

0 < x < 75mm <

x

< 100mm <

x

< 125mm <

x









W





W







V

WYX

Z

background image



















































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Document Outline


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