Ch. 15-09 Build a Model Solution |
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3/6/2001 |
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Chapter 15. Solution to Ch. 15-09 Build a Model |
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Assume you have been given the following information on Purcell Industries: |
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P |
$15 |
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X |
$15 |
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t |
0.5 |
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r |
10% |
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s2 |
0.12 |
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Using the Black-Scholes Option Pricing Model, what would be the value of the option? |
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First, we will use formulas from the text to solve for d1 and d2. |
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Hint: use the NORMSDIST function. |
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(d1) |
= |
0.327 |
N(d1) = |
0.628014260962472 |
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(d2) |
= |
0.082 |
N(d2) = |
0.532537344178941 |
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Using the formula for option value and the values of N(d) from above, we can find the call option value. |
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V |
= |
$1.822 |
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a. Construct data tables for the intrinsic value and Black-Scholes formula value for this option, and graph |
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this relationship. Include possible stock price values ranging up to $27. |
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Option Value |
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Current |
Intrinsic |
B-S formula |
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Exercise |
stock |
Value |
Value |
Option |
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Price |
price |
$0 |
$1.822 |
Premium |
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$15.00 |
$1.00 |
$0.00 |
$0.00 |
$0.00 |
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$15.00 |
$3.00 |
$0.00 |
$0.00 |
$0.00 |
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$15.00 |
$6.00 |
$0.00 |
$0.00 |
$0.00 |
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$15.00 |
$9.00 |
$0.00 |
$0.03 |
$0.03 |
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$15.00 |
$12.00 |
$0.00 |
$0.45 |
$0.45 |
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$15.00 |
$15.00 |
$0.00 |
$1.82 |
$1.82 |
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$15.00 |
$18.00 |
$3.00 |
$4.09 |
$1.09 |
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$15.00 |
$21.00 |
$6.00 |
$6.83 |
$0.83 |
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$15.00 |
$24.00 |
$9.00 |
$9.76 |
$0.76 |
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$15.00 |
$27.00 |
$12.00 |
$12.74 |
$0.74 |
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c. Suppose this call option is purchased today, draw the profit diagram of this option position at expiration. |
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XCALL = |
$15 |
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if P= … |
Call |
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$1 |
-$1.82 |
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$3 |
-$1.82 |
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$6 |
-$1.82 |
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$9 |
-$1.82 |
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$12 |
-$1.82 |
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$15 |
-$1.82 |
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$18 |
$1.18 |
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$21 |
$4.18 |
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$24 |
$7.18 |
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$27 |
$10.18 |
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