F

1

1



F

2

1



F

3

1



F

4

1



Given

1.3286F

1

0F

2



0.0276F

3



0.4286F

4



9.1875



=

0F

1

0.9762F

2



0.5510F

3



0.3690F

4



0

=

0.0276F

1

0.5510 F

2





2.5215F

3



0.5510F

4



48.375



=

0.4286



F

1

0.3690 F

2





0.5510



(

)F

3



2.0040



(

)F

4



27.5625



=

Find F

1

F

2



F

3



F

4







16.517



30.458

32.623



31.864



















