02 Calka Krzywoliniowa N odpowiedzi

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

1

Zad.1

(

)

dl

y

x

L

+

2

2

( )

1

,

1

A

;

( )

4

,

4

B

+

=

+

=

b

a

b

a

4

4

1

=

=

0

1

b

a

x

y

=

1

'

=

y

(

)

3

2

126

2

2

1

1

4

1

2

4

1

2

2

=

=

+

+

dx

x

dx

x

x

Zad.2

(

)

L

dl

y

x

2

( )

2

,

2

A

;

(

)

4

,

2

B

+

=

+

=

b

a

b

a

2

4

2

2

=

=

3

2

1

b

a

3

2

1 +

=

x

y

2

1

'

=

y

5

6

3

4

5

2

5

3

2

5

2

5

2

1

1

3

2

1

2

2

2

2

2

2

2

2

2

=

=

=

+

+

x

x

dx

x

dx

x

x

Zad.3

( )

L

dl

y

x

y

4

2

=

( )

0

,

0

O

;

( )

2

,

1

P

( )

x

x

y

1

1

'

2

2

=

=

(

)

1

8

3

4

3

4

2

1

1

2

1

2

2

1

2

3

2

1

1

0

1

0

=

=

=

=

=

+

=

+

=

+

t

dx

t

dt

dx

t

x

dx

x

dx

x

x

x

Zad.4

( )

L

dl

y

3

x

y

=

( )

1

,

1

A

;

( )

8

,

2

B

( )

( )

4

2

2

2

9

3

'

x

x

y

=

=

(

)

3

3

145

10

3

145

10

2

3

2

4

2

1

4

3

10

145

54

1

54

1

18

1

18

1

9

1

9

1

=

=

=

=

=

+

=

+

t

dt

t

tdt

dx

x

t

x

dx

x

x

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

2

Zad.5

L

dl

y

x

4

x

y

1

=

2

1

x

( )

4

2

2

2

1

1

'

x

x

y

=

=

(

)

2

2

17

17

6

1

6

1

2

1

2

1

1

1

1

17

2

3

17

2

2

3

2

4

4

2

1

3

4

4

2

1

5

=

=

=

=

=

+

=

+

=

+

t

dt

t

tdt

dx

x

t

x

dx

x

x

dx

x

x

x

Zad.6

( )

dl

x

y

L

cos

2

( )

x

y sin

=

2

0

π

x

( )

( )

x

y

2

2

cos

'

=

( ) ( )

( )

( )

( ) ( )

(

)

1

2

2

3

2

3

2

2

sin

cos

cos

1

cos

1

cos

sin

2

1

2

3

1

2

2

2

2

2

2

0

=

=

=

=

=

+

=

+

t

dt

t

tdt

dx

x

x

t

x

dx

x

x

x

π

Zad.7

+

L

dl

x

4

9

1

x

x

y

=

4

0

x

( )

x

x

y

4

9

2

3

'

2

2

=

=

22

18

4

8

9

4

9

1

4

9

1

4

9

1

4

0

2

4

0

4

0

=

+

=

+

=

+

=

+

+

x

x

dx

x

dx

x

x

Zad.8

(

)

+

L

dl

y

x

( )

0

,

0

O

;

( )

0

,

1

A

;

( )

1

,

0

B

=

=

=

=

+

=

1

0

0

:

1

0

0

:

1

0

1

:

3

2

1

t

t

x

y

l

t

t

y

x

l

x

x

y

l

(

)

(

)

=

=

+

+

=

1

0

1

0

2

2

1

1

1

1

dx

dx

x

x

dl

y

x

l

(

)

=

+

=

1

0

2

1

1

0

2

dt

t

dl

y

x

l

(

)

=

+

=

1

0

2

1

0

1

3

dt

t

dl

y

x

l

(

)

2

1

2

1

2

1

2

+

=

+

+

=

+

L

dl

y

x

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

3

Zad.9

dl

xy

L

2

6

( )

t

x

cos

3

1

=

( )

t

y

sin

3

1

=

4

0

π

t

( )

( )

( )

t

t

x

2

2

2

sin

9

1

sin

3

1

'

=

=

( )

( )

( )

t

t

y

2

2

2

cos

9

1

cos

3

1

'

=

=

( )

( )

( )

( )

( )

( )

162

2

648

2

81

2

27

2

cos

sin

sin

cos

27

2

9

1

sin

9

1

cos

3

1

6

2

5

2

2

0

3

2

2

0

2

2

4

0

2

4

0

=

=

=

=

=

=

=

=

u

du

u

du

dt

t

u

t

dt

t

t

dt

t

t

π

π

Zad.11

+

L

dl

y

xz

2

1

t

x

= ;

2

t

y

= ;

3

3

2

t

z

=

1

0

t

( )

1

'

2

=

x

( )

2

2

4

'

t

y

=

( )

4

2

4

'

t

z

=

(

)

15

2

3

2

2

1

2

1

3

2

4

4

1

2

1

3

2

1

0

4

2

2

1

0

2

4

4

2

1

0

2

4

=

=

+

+

=

+

+

+

dt

t

dt

t

t

t

dt

t

t

t

t

Zad.12

( )

L

dl

xy

t

e

x

= ;

t

e

y

=

;

t

z

2

=

1

0

t

( )

t

e

x

2

2

'

=

( )

t

e

y

2

2

'

=

( )

2

'

2

=

z

( )

(

)

( )

=

+

=

+

+

=

+

+

=

+

+

dt

e

e

dt

e

e

e

dt

e

e

dt

e

e

e

e

t

t

t

t

t

t

t

t

t

t

t

1

0

2

2

2

1

0

2

2

2

2

1

0

2

2

2

2

1

0

1

1

2

2

2

(

) (

) (

)

1

1

0

1

0

1

1

0

2

1

1

1

=

+

=

=

+

=

+

=

e

e

e

e

e

e

dt

e

e

dt

e

e

t

t

t

t

t

t

Zad.13

(

)

+

L

dl

z

y

x

( )

t

x cos

=

( )

t

y sin

=

t

z

4

3

=

π

2

0

t

( )

( )

t

x

2

2

sin

'

=

( )

( )

t

y

2

2

cos

'

=

( )

16

9

'

2

=

z

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

4

( ) ( )

( ) ( )

( )

( )

( )

=

=

=

=

+

=

+

+

du

dt

t

u

t

dt

t

t

t

t

dt

t

t

t

cos

sin

cos

4

3

sin

cos

4

5

16

9

1

4

3

sin

cos

2

0

2

0

π

π

( )

( )

( )

( )

( )

(

)

( )

( )

0

cos

16

15

sin

sin

16

15

sin

1

'

cos

'

cos

16

15

4

5

2
0

2

0

2
0

2

0

0

0

=

=

=

=

=

=

=

=

+

π

π

π

π

t

dt

t

t

t

t

q

p

t

q

t

p

dt

t

t

du

u

Zad.14

( )

L

dl

z

( )

t

t

x

cos

=

( )

t

t

y

sin

=

t

z

=

1

0

t

( )

( )

( )

(

)

( )

( ) ( )

( )

t

t

t

t

t

t

t

t

t

x

2

2

2

2

2

sin

sin

cos

2

cos

sin

cos

'

+

=

=

( )

( )

( )

(

)

( )

( ) ( )

( )

t

t

t

t

t

t

t

t

t

y

2

2

2

2

2

cos

sin

cos

2

sin

cos

sin

'

+

+

=

+

=

( )

1

'

2

=

z

(

)

2

2

3

3

3

1

3

1

2

2

1

1

3

2

3

3

2

2

2

2

1

0

2

1

0

2

=

=

=

=

=

+

=

+

=

+

+

u

du

u

udu

tdt

u

t

dt

t

t

dt

t

t

Zad.15

=

L

dl

L

( )

x

y ln

=

5

2

x

( )

2

2

1

'

x

y

=

( )

(

)

( )

=

+

+

=

=

+

=

=

+

=

=

+

=

+

=

5

2

2

5

2

2

2

2

1

2

5

2

2

5

2

2

1

1

1

1

'

ln

'

1

1

ln

1

1

x

dx

x

x

x

v

x

x

u

x

v

x

u

dx

x

x

dx

x

L

(

)

(

) (

)

+

+

+

=

+

+

+

=

+

+

=

26

5

5

2

ln

2

5

5

26

5

2

ln

26

5

ln

2

5

5

26

1

ln

2

5

5

26

5

2

2

x

x

Zad.16

=

L

dl

L

( )

t

x

cos

7

=

( )

t

y

sin

7

=

π

4

3

0

t

( )

( )

t

x

2

2

sin

49

'

=

( )

( )

t

y

2

2

cos

49

'

=

4

21

7

49

4

3

0

4

3

0

π

π

π

=

=

=

dt

dt

L

Zad.17

( )

γ

γ

cos

1

+

=

r

π

γ

0

(

)

(

)

+

=

+

=

γ

γ

γ

γ

sin

cos

1

cos

cos

1

:

y

x

L

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

5

(

)

(

)

γ

γ

γ

γ

γ

γ

γ

cos

cos

1

sin

'

sin

cos

1

cos

sin

'

2

+

+

=

+

=

y

x

( )

(

) (

)

( )

(

)

(

)

γ

γ

γ

γ

γ

γ

γ

γ

γ

γ

γ

γ

γ

2

2

2

4

2

2

2

2

2

2

2

cos

cos

1

cos

sin

cos

1

2

sin

'

sin

cos

1

cos

1

cos

sin

2

cos

sin

'

+

+

+

=

+

+

+

+

=

y

x

( )

γ

γ

sin

'

=

r

( ) ( )

( )

[

]

( )

[ ]

γ

γ

2

2

2

2

'

'

'

r

r

y

x

+

=

+

( ) ( )

(

)

(

)

γ

γ

γ

γ

γ

γ

cos

1

2

cos

cos

2

1

sin

cos

1

sin

'

'

2

2

2

2

2

2

2

+

=

+

+

+

=

+

+

=

+

y

x

( )

(

)

4

2

sin

4

2

cos

2

2

cos

2

2

cos

1

2

,

0

0

0

2

0

=

=

=

=

+

=

=

π

π

π

π

γ

γ

γ

γ

γ

γ

γ

d

d

d

dl

y

x

f

L

L

Zad.18

( )

=

γ

γ

3

1

sin

3

3

r

( )

( )

=

=

γ

γ

γ

γ

sin

3

1

sin

3

cos

3

1

sin

3

:

3

3

y

x

L

( )

( )

γ

γ

γ

γ

γ

sin

3

1

sin

3

cos

3

1

cos

3

1

sin

3

'

3

2

=

x

( )

( )

γ

γ

γ

γ

γ

cos

3

1

sin

3

sin

3

1

cos

3

1

sin

3

'

3

2

+

=

y

( )

( )

γ

γ

2

2

2

2

'

'

'

r

r

y

x

+

=

+

( )

=

γ

γ

γ

3

1

cos

3

1

sin

3

'

2

r

=

+

=

+

=

+

γ

γ

γ

γ

γ

γ

3

1

sin

3

1

cos

3

1

sin

9

3

1

sin

3

3

1

cos

3

1

sin

3

'

'

2

2

4

2

3

2

2

2

2

y

x

=

=

γ

γ

3

1

sin

3

3

1

sin

9

2

4

( )

( )

π

α

α

α

γ

α

γ

γ

γ

π

π

2

9

sin

9

3

3

1

3

1

sin

3

,

0

2

3

0

2

=

=

=

=

=

=

d

d

d

dl

y

x

f

L

L

( )

( ) ( )

( )

( )

( )

( )

( ) ( )

[

]

( )

=

+

=

=

=

=

=

=

=

π

π

π

π

α

α

α

α

α

α

α

α

α

α

α

α

α

0

2

0

0

0

2

cos

cos

sin

cos

cos

'

sin

'

sin

sin

sin

sin

)

d

v

u

v

u

d

d

( )

(

)

( )

( )

2

sin

sin

sin

1

0

0

2

0

2

0

2

π

α

α

α

α

π

α

α

π

π

π

=

=

+

=

d

d

d

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

6

Zad.19

2

,

1

A

11

,

11

B

( )

30

,

2

2

y

x

y

x

+

=

ρ

+

=

+

=

b

a

b

a

11

11

2

=

=

4

11

4

3

b

a

4

11

4

3

+

=

x

y

( )

16

9

4

3

'

2

2

=

=

y

( )

=

+

=

+

+

=

=

1

11

2

1

11

2

2

16

121

8

33

16

25

24

1

16

9

1

4

3

4

11

30

1

,

dx

x

x

dx

x

x

dl

y

x

M

L

ρ

43

1152

49536

1152

16236

33300

384

1452

3960

1152

33300

384

121

384

33

1152

25

1

11

2

3

=

=

+

=

+

+

=

+

=

x

x

x

Zad.20

x

y

=

2

0

x

( )

x

x

y

x

=

,

ρ

( )

4

2

2

2

1

1

'

x

x

y

=

=

( )

=

+

=

+

=

+

=

=

dx

x

x

dx

x

x

x

x

dx

x

x

x

dl

y

x

M

L

2

0

4

4

2

0

2

4

2

0

1

1

1

1

,

ρ

Zad.21

x

e

y

2

=

1

0

x

( )

2

,

y

y

x

=

ρ

( )

(

)

x

x

e

e

y

4

2

2

2

4

2

'

=

=

( )

=

=

=

=

+

=

+

=

=

+

4

4

1

5

4

4

4

1

0

4

16

1

16

1

4

1

4

1

,

e

x

x

x

x

L

dt

t

dt

dx

e

t

e

dx

e

e

dl

y

x

M

ρ

(

)

+

=

− 3

4

3

4

1

5

24

1

e

Zad.22

( )

( )

=

=

=

t

z

t

y

t

x

3

2

sin

4

2

cos

4

π

2

0

t

(

)

π

ρ

2

1

,

,

t

y

x

+

=

( )

( ) ( )

(

)

( )

( )

( )

( ) ( )

(

)

( )

( )

( )

=

=

=

=

=

9

'

2

sin

2

cos

64

2

sin

2

cos

8

'

2

sin

2

cos

64

2

sin

2

cos

8

'

2

2

2

2

2

2

2

2

2

z

t

t

t

t

y

t

t

t

t

x

(

)

( ) ( )

=

+

+

=

=

dt

t

t

t

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128

9

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1

,

,

background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

7

Zad.23

2

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Zad.24

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Zad.25

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background image

Grzegorz Mrzygłocki, WILi , sem. III, gr.2

8

Zad.26

x

e

y

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1

0

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=

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Zad.27

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2

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Zad.28

=

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2

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x

(

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d


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